if you want to remove an article from website contact us from top.

# make a diagram to show how hypermetropia is corrected. the near point of a hypermetropic eye is 1 m. what is the power of the lens required to correct this defect? assume that the near point of the normal eye is 25 cm.

Category :

### Mohammed

Guys, does anyone know the answer?

get make a diagram to show how hypermetropia is corrected. the near point of a hypermetropic eye is 1 m. what is the power of the lens required to correct this defect? assume that the near point of the normal eye is 25 cm. from screen.

## Make a diagram to show how hypermetropia is corrected. The near point of hypermetropic eye is 1 m. What is the power of lens required to correct this defect? Assume that the near point of the normal eye is 25 cm.

Click here👆to get an answer to your question ✍️ Make a diagram to show how hypermetropia is corrected. The near point of hypermetropic eye is 1 m. What is the power of lens required to correct this defect? Assume that the near point of the normal eye is 25 cm. Question

## Make a diagram to show how hypermetropia is corrected. The near point of hypermetropic eye is 1 m. What is the power of lens required to correct this defect? Assume that the near point of the normal eye is 25 cm.

Medium Open in App

Updated on : 2022-09-05

Solution Verified by Toppr

Hypermetropia can be corrected by using a convex lens. A convex lens converges the incoming light such that the image is formed on the retina.

An object at 25 cm forms an image at the near point of the hypermetropic eye. Here, near point is 1 m.

Given,

Object distance,u=−25 cm

Image distance, v=−100 cm

From lens formula, v 1 ​ − u 1 ​ = f 1 ​ −100 1 ​ − −25 1 ​ = f 1 ​

Focal length,f=100/3 cm=1/3 m

Power, P= f 1 ​ = 1/3 1 ​ =3 D Video Explanation 187 25

स्रोत : www.toppr.com

## Make a diagram to show how hypermetropia is corrected. The near point of a hypermetropic eye is 1 m. What is the power of the lens required to correct this defect? Assume that the near point of the normal eye is 25 cm.

Make a diagram to show how hypermetropia is corrected. The near point of a hypermetropic eye is 1 m. What is the power of the lens required to correct this defect? Assume that the near point of the normal eye is 25 cm. - Get the answer to this question and access a vast question bank that is tailored for students. Academic QuestionsPhysics QuestionsMake A Diagram To Show How Hypermetropia Is Corrected The Near Point Of A Hypermetropic Eye Is 1 M What Is The Power Of The Lens Required To Correct This Defect ## Make a diagram to show how hypermetropia is corrected. The near point of a hypermetropic eye is 1 m. What is the power of the lens required to correct this defect? Assume that the near point of the normal eye is 25 cm.

Hypermetropia is also known as hyperopia or long-sightedness or far-sightedness. Hypermetropia is the condition of the eyes where the image of a nearby object is formed behind the retina. Here, the light is focused behind the retina instead of focusing on the retina. Hypermetropia is mainly caused due to certain structural defects in the retina. Structural defects comprise of:

Small-sized eye-ball

Non-circular lenses

The cornea is flatter than usual

Defective blood vessels in the retina The convex lens creates a virtual image of a nearby object (N’ in the above figure) at the near point of vision (N) of the individual suffering from hypermetropia.

The given individual will be able to clearly see the object kept at 25 cm (near the point of the normal eye) if the image of the object is formed at his near point, which is given as 1 m.

Object distance, u= – 25 cm

Image distance, v= – 1 m = – 100 m

Focal length, f

Using the lens formula,

1v−1u=1f = −1100−1−25=1f = 1f=−125−1100 =

1f=−4−1100=3100=0.33m

Power= 1/f = 1/0.33 = +3.0 D

3.5 (24)

Related Questions & Answers

Which Chlorides Does Li And Mg Form

A Good Conductor Of Heat Is

Which Of The Following Is True For A Forward Biased Diode

Name The Microorganisms Which Can Fix Atmospheric Nitrogen In The Soil

Resonant Circuits Are Used In Tuning Of

For A Step Up Transformer

What Term Is Used To Describe 14si28 And 14si29

What Is The Function Of Olfactory Receptors

Which Of The Following Statements Is Not True For Polar Molecules

Action And Reaction Forces Are Always What

स्रोत : byjus.com

## Make a diagram to show how hypermetropia is corrected. The near point of a hypermetropic eye is 1 metre. What is the power of the lens required to correct this defect ? Assume that the near point of the normal eye is 25 cm.

A person suffering from hypermetropia can see distinct objecdts clearly but faces difficulty is seeing nearly objects clearly. It happens because the eye lense focuses the incoming diverget rays beyond the ratina. This defect of vision is corrected by using a convex lens. A convex lens of suitable power converges the incoming light in such a way that the image is formed on the retina, as shown in the following firgure . The convex lens actually creates a virtual image of a nearby object (N'in hte figure ) at the near point of vision (N) of the perosn suffering from hyermetropia. The given perons wil be able to clearly see the object kept at 25 cm (near point of the normal eye). if the image of the object is formed at his near point, which is given as 1 m Object distance , u=-25 cm Image distance , v=-1m =-100m Focal length ,f Using the lens formula, (1)/(v)-(1)/(u)=(1)/(f) -(1)/(100)-(1)/(-25)=(1)/(f) (1)/(f)=-(1)/(25)=(1)/(100) (1)/(f)=-(4-1)/(100) f=(100)/(3)=33.3 cm=0.33m We known, Powr , P=(1)/(f(" in meteres")) P=(1)/(0.33)=+30.0D A convex lens of power +3.0 D is required to correct the defect.

Home > English > Class 10 > Physics > Chapter >

The Human Eye And Colourful World

>

Make a diagram to show how hyp...

Make a diagram to show how hypermetropia is corrected. The near point of a hypermetropic eye is

1metre 1metre

. What is the power of the lens required to correct this defect ? Assume that the near point of the normal eye is

25cm 25cm .

Updated On: 27-06-2022

Get Answer to any question, just click a photo and upload the photo and get the answer completely free,

UPLOAD PHOTO AND GET THE ANSWER NOW!

Text Solution Open Answer in App Solution

A person suffering from hypermetropia can see distinct objecdts clearly but faces difficulty is seeing nearly objects clearly. It happens because the eye lense focuses the incoming diverget rays beyond the ratina. This defect of vision is corrected by using a convex lens. A convex lens of suitable power converges the incoming light in such a way that the image is formed on the retina, as shown in the following firgure .

The convex lens actually creates a virtual image of a nearby object (N'in hte figure ) at the near point of vision (N) of the perosn suffering from hyermetropia.

The given perons wil be able to clearly see the object kept at 25 cm (near point of the normal eye). if the image of the object is formed at his near point, which is given as 1 m

Object distance , u=-25 cm

Image distance , v=-1m =-100m

Focal length ,f

Using the lens formula,

1 v − 1 u = 1 f 1v-1u=1f − 1 100 − 1 −25 = 1 f -1100-1-25=1f 1 f =− 1 25 = 1 100 1f=-125=1100 1 f =− 4−1 100 1f=-4-1100 f= 100 3 =33.3cm=0.33m f=1003=33.3cm=0.33m We known, Powr , P= 1 f( in meteres) P=1f( in meteres) P= 1 0.33 =+30.0D P=10.33=+30.0D

A convex lens of power +3.0 D is required to correct the defect.

Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

Transcript

hello friends in the person we have to make a diagram to show hypermetropia is corrected ok the near point of a hypermetropic eye is given here as one metre and where to find the power of lens required to correct this defect ok and we have to assume that in your point of the normalised 25cm so in hypermetropia ok in hypermetropia the images formed behind the retina letters in image formed on the retina behind ok behind retina object of its focus at point P which is behind the retina ok so we have to increase the converging power of the islands ok and to do so we introduce

dance in front of the islands ok let's say that we introduce the convex lens like this ok in front of the US as a country for this configuration the image of an object placed at O you can see the image of an object placed at home that is the normal near point of the eye is formed on retina and for the man it it appears to be at at the point of the man ok object is at the near point of normalised that is 25 CM OK then the image formed is at order that the near point of the men and hear the year

1 metre is equal to we will be -103 needs to find formula we know that 1 upon 3 minus 1 upon 2 is equal to 1 upon from here we can say one upon this because this that lets you search CV 200 CM upon my hundred minus one upon us -25 and this will be equal to 1 upon focal length of a convex lens used ok that we can say this minus 5 minus plus sandal get one upon 25 - 100 to 1 upon

focal length f OK so the power will be What power will be one upon f and one upon us is as a hundred ok and those that the current 4 - 1 + 1 upon F3 upon hundred universe ok to convert it into m inverse will get World War I will multiply it with with hundred and that is will get three major inverse X hundred ok and does will get power as one upon us and power will be able to diopter it and see that the connections will be used with the power of three drive axle for this question guys thank you

## Related Videos 571228469 0 2.8 K 4:00

Make a diagram to show how hypermetropia is corrected. The near point of a hypermetropic eye is

1metre 1metre

. What is the power of the lens required to correct this defect ? Assume that the near point of the normal eye is

25cm 25cm . 380026840 0 6.9 K 4:02

Make a diagram to show how hypermetropia is corrected. The near point of a hypermetropia eye is 1m. What is the power of the lens required to correctt this defect ? Assume that the near point of the normal eye is 25 cm. 31587473 0 4.4 K 3:40

(a) Make a diagram to show how hypermetropia is corrected (b) The near point of a hypermetropic eye is 1 m. What is the power of the lens required to correct this defect ? Assume that the near point of the normal eye is 25 cm .

स्रोत : www.doubtnut.com

Do you want to see answer or more ?
Mohammed 6 day ago

Guys, does anyone know the answer?