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# mean of 46 items is 30. it was discovered that three items which should have been 33, 38, 39 were wrongly read as 25, 30, 35 respectively. the correct mean is

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### Mohammed

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get mean of 46 items is 30. it was discovered that three items which should have been 33, 38, 39 were wrongly read as 25, 30, 35 respectively. the correct mean is from screen.

## Mean of 100 items is 49 . It was discovered that three items which should have been 60,70,80 were wrongly read as 40,20,50 respectively. The correct mean is

Click here👆to get an answer to your question ✍️ Mean of 100 items is 49 . It was discovered that three items which should have been 60,70,80 were wrongly read as 40,20,50 respectively. The correct mean is Question

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## Mean of 100 items is 49. It was discovered that three items which should have been 60, 70, 80 were wrongly read as 40, 20, 50 respectively. The correct mean is ______.

Mean of 100 items is 49. It was discovered that three items which should have been 60, 70, 80 were wrongly read as 40, 20, 50 respectively. The correct mean is ______. Mean of 100 items is 49. It was discovered that three items which should have been 60, 70, 80 were wrongly read as 40, 20, 50 respectively. The correct mean is ______.

### SOLUTION

Mean of 100 items is 49. It was discovered that three items which should have been 60, 70, 80 were wrongly read as 40, 20, 50 respectively. The correct mean is 50.

Explanation:-

Sum of 100 observations

= 100 × 49 = 4900 Correct sum

= 4900 - [40 + 20 + 50 ] + [60 + 70 + 80] = 5000

∴ Correct mean = 5000100=50

Concept: Mean of Grouped Data

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## The mean of 50 numbers is 30. Later it was discovered that two entries were wrongly entered as 82 and 13 instead of 28 and 31. Find the correct mean.

The mean of 50 numbers is 30. Later it was discovered that two entries were wrongly entered as 82 and 13 instead of 28 and 31. Find the correct mean.

Average

## The mean of 50 numbers is 30. Later it was discovered that two entries were wrongly entered as 82 and 13 instead of 28 and 31. Find the correct mean.

A) 36.12 B) 30.66 C) 29.28 D) 38.21 Correct Answer: C) 29.28

According to the question

The mean of 50 no. is = 30

Sum of 50 no. is = 50×30=1500 50×30=1500

later it was discovered that two entries were wrongly entered as 82 and 13 instead of 28 and 31.

∴ ∴

Difference = (82 + 13) - (28 + 31) = 95 - 59 = 36 (Extra)

∴ ∴

Actual sum of 50 numbers is 1500 - 36 = 1464

∴ ∴ Actual avg. 1464 50 =29.28 146450=29.28

Part of solved Average questions and answers : >> Aptitude >> Average

1). The average of 25 observations is 13. It was later found that an observation 73 was wrongly entered as 48. The new average is

2). Mean of 10 numbers is 30. Later on it was observed that numbers 15, 23 are wrongly taken as 51,32. The correct mean is

3). The mean value of 20 observations was found to be 75, but later on it was detected that 97 was misread as 79. Find the correct means.

4). The mean of 100 items was 46. Later on it was discovered that an item 16 was misread as 61 and another item 43 was misread as 34. It was also found that the number of items was 90 and not 100. Then what is the correct mean ?

5). The average of seven numbers is 18. If one of the number is 17 and if it is replaced by 31, the average becomes :

6). In an exam, the average marks obtained by the students was found to be 60. After omission of computational errors, the average marks of 100 candidates had to be changed from 60 to 30 and the average with respect to all the examinees came down to 45 marks. The total number of candidates who took the exam, was

7). The average of 10 items was found to be 80 but while calculating, one of the items was counted as 60 instead of 50. Then the correct average would have been :

8). A student finds the average of 10, 2 digits numbers. If the digit its of one of the numbers is interchanged, the average increases by 3.6. The difference between the digits of the 2 digit its number is

9). The average marks obtained by a student in 6 subjects is 88. On subsequent verification it was found that the marks obtained by him in a subject was wrongly copied as 86 instead of 68. The correct average of the marks obtained by him is: