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# name the physical quantity which can be expressed by the ratio of the amplitude of electric field to the magnetic field in an electromagnetic wave.

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## In electromagnetic waves the ratio of amplitudes of electric field and magnetic field is equal to

In electromagnetic waves the ratio of amplitudes of electric field and magnetic field is equal to Here we give solutions for every questions you ask us

Wave Equation of EM Waves

In electromag... Question

In electromagnetic waves, the ratio of amplitudes of the electric field and the magnetic field is equal to

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Electromagnetic Waves

Electromagnetic waves are types of transverse waves since their direction of vibration is perpendicular to their direction of propagation.

In an electromagnetic wave, there is a time-varying electric field and magnetic field.

The electric field, magnetic field, and direction of propagation are all mutually perpendicular to each other.

These electric fields and magnetic fields are mutually generated by both fields according to the principles of electromagnetic induction.

Therefore electromagnetic waves do not require a medium and can travel in a vacuum.

Light is a form of electromagnetic wave.

Ratio of Amplitudes

The amplitude of electric field is given as

ε

and the amplitude of magnetic field is given as

μ . We can identify εμ as 1v2 where v

is the speed of the wave.

∴v=1εμ For free space ε=ε0=8.854×10-12F/m and π π μ=μ0=4π×10-7H/m . ∴v=c=1ε0μ0 ≈3×108m/s

This agrees with the speed of light in free space.

Hence, in electromagnetic waves in free space, the ratio of amplitudes of the electric field and the magnetic field is equal to the speed of light.

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SIMILAR QUESTIONS

Q.

The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is 0 = 510 nT. What is the amplitude of the electric field part of the wave?

Q.

In electromagnetic waves the ratio of amplitudes of electric field and magnetic field is equal to

Q. The ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagating in vacuum is equal toQ. Write the relation for the speed of electromagnetic waves and the amplitudes of electric and magnetic fields.Q. The amplitude of the magnetic field of a harmonic electromagnetic wave in vacuum is

B 0

= 510 nT. The amplitude of the electric field part of the wave is

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## What is ratio of electric field and magnetic field in EM wave?

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Updated on : 2022-09-05

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In electromagnetic waves the ratio of amplitudes of electric field and magnetic field is equal to. In electromagnetic waves the ratio of amplitudes of electric field and magnetic field is equal to the velocity of the electromagnetic waves in free space.

E/B = v

Solve any question of Electromagnetic Waves with:-

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Choose the correct answer from the alternatives given.

21 1 SIMILAR QUESTIONS

Suppose that the electric field amplitude of an electromagnetic wave propagating along x-direction is E

0 ​ = 120 N C −1

and that frequency is: υ = 50.0 MHz.

Which of the following have zero average value in a plane electromagnetic wave?

Medium View solution > (i) Magnetic field (ii) Electric field

(iii) Electric energy

(iv) Magnetic energy.

An electromagnetic wave with frequency ω and wavelength λ travels in the +y direction. Its magnetic field is along −x axis. The vector equation for the associated electric field (of amplitude E

Hard View solution > 0 ​ )is : Hard View solution >

### The waves that are propagated by simultaneous periodic variations of electric and magnetic field intensity known as:

The ratio of contributions made by the electric field and magnetic field components to the intensity of an electromagnetic wave is :

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(c = speed of electromagnetic waves)

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## The ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagating in vacuum is equal toA.Reciprocal of speed of light in vacuumB.The ratio of magnetic permeability to the electric susceptibility of vacuumC.UnityD.The speed of light in vacuum

The ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagating in vacuum is equal toA.Reciprocal of speed of light in vacuumB.The ratio of magnetic permeability to the electric susceptibility of va...

The ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagating in vacuum is equal to

A.Reciprocal of speed of light in vacuum

B.The ratio of magnetic permeability to the electric susceptibility of vacuum

C.Unity

D.The speed of light in vacuum

Last updated date: 14th Mar 2023

• Total views: 210.5k • Views today: 1.91k Answer Verified 210.5k+ views 1 likes

Hint: To solve this question firstly we should understand the concept of magnetic field and electric field and all the related information. We will also study the relation between the electric field and magnetic field. And by this information, we will easily approach our answer.Complete answer:

A magnetic field is a vector quantity that describes the magnetic influence or an electric charge of another moving charge. A charge that is a magnetic field that is perpendicular to its own velocity and magnetic field.

Electric fields surround an electric charge and exert force on the charge of electric fields attracting or repelling it.

Electric field and magnetic field both are interrelated to each other and both are components of electromagnetic waves.

We know that, ⇒C= E 0 B 0 ⇒ B 0 E 0 = 1 C ⇒C=E0B0⇒B0E0=1C

Therefore, the ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave in a vacuum is equal to the reciprocal of speed of light.

Hence, the correct option is A - Reciprocal of speed of light in vacuum

Note: The way in which electric field and magnetic field interact each other is described in Maxwell and Lorentz force law. The force exerted by the electric field is much stronger than the force exerted by the magnetic field.

Also, Magnetic energy density is equal to the electrical energy density, in an electromagnetic wave.

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Mohammed 9 day ago

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