susan invested certain amount of money in two schemes a and b, which offer interest at the rate of 8% per annum and 9% per annum, respectively. she received rs 1860 as annual interest. however, had she interchanged the amount of investments in the two schemes, she would have received rs 20 more as annual interest. how much money did she invest in each scheme?
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get susan invested certain amount of money in two schemes a and b, which offer interest at the rate of 8% per annum and 9% per annum, respectively. she received rs 1860 as annual interest. however, had she interchanged the amount of investments in the two schemes, she would have received rs 20 more as annual interest. how much money did she invest in each scheme? from screen.
Susan invested certain amount of money in two schemes A and B , which offer interest at the rate of 8% per annum and 9% per annum, respectively. She received Rs. 1860 as annual interest. However, had she interchanged the amount of investments in the two schemes, she would have received Rs. 20 more as annual interest. How much money did she invest in each scheme?
Click here👆to get an answer to your question ✍️ Susan invested certain amount of money in two schemes A and B , which offer interest at the rate of 8% per annum and 9% per annum, respectively. She received Rs. 1860 as annual interest. However, had she interchanged the amount of investments in the two schemes, she would have received Rs. 20 more as annual interest. How much money did she invest in each scheme?
Question
Susan invested certain amount of money in two schemes A and B, which offer interest at the rate of 8% per annum and 9% per annum, respectively. She received Rs. 1860 as annual interest. However, had she interchanged the amount of investments in the two schemes, she would have received Rs. 20 more as annual interest. How much money did she invest in each scheme?
ARs. 13000 in scheme A, Rs. 12000 in scheme B
BRs. 12000 in scheme A, Rs. 10000 in scheme B
CRs. 11000 in scheme A, Rs. 10000 in scheme B
DRs. 10000 in scheme A, Rs. 13000 in scheme B
Medium Open in App Solution Verified by Toppr
Correct option is B)
Let amount invested in A be Rs. x and in B be Rs. y.
As per the given statements, 0.08x+0.09y=1860.....(1)
And, 0.09x+0.08y=1880.....(2)
Multiplying equation (1) with 8 we get, 0.64x+0.72y=14880.....(3)
Multiplying equation (2) with 9 we get, 0.81x+0.72y=16920.....(4)
Subtracting equation (3) from (4), we get 0.17x=2040=>x=12000
Substituting x=12000 in the equation (1), we get 0.08(12000)+0.09y=1860⇒y=10000
Hence, amount invested A is Rs. 12000 and in B is Rs. 10000
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Susan invested certain amount of money in two schemes A and B which offer interest at the rate of 8 ...
Free solutions for Mathematics Exemplar Problems - class 10 Chapter 4 - Pair of Linear Equations in Two Variables Pair of Linear Equations in Two Variables - Exercise 3.4 question 11. These explanations are written by Lido teacher so that you easily understand even the most difficult concepts
NCERT Exemplar Solutions Class 10 Mathematics Solutions for Pair of Linear Equations in Two Variables - Exercise 3.4 in Chapter 3 - Pair of Linear Equations in Two Variables
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Susan invested certain amount of money in two schemes A and B, which offer interest at the rate of 8% per annum and 9% per annum, respectively. She received ₹1860 as annual interest. However, had she interchanged the amount of investments in the two schemes, she would have received ₹20 more as annual interest. How much money did she invest in each scheme ?
Answer:
Let the money invested in scheme A =₹x
and the money invested in scheme B = ₹y
Case I: Susan invested ₹ x at 8% p.a. + Susan invested ₹y at 9% p.a. = 1860\begin{array}{l} \Rightarrow \frac{x \times 8 \times 1}{100}+\frac{y \times 9 \times 1}{100}=1860 \\ \Rightarrow 8 \mathrm{x}+9 \mathrm{y}=186000 \ldots(\mathrm{i}) \end{array}
⇒ 100 x×8×1 + 100 y×9×1 =1860 ⇒8x+9y=186000…(i)
Case II: Interchanging the amount in schemes A and B, we have\frac{9 \times x}{100}+\frac{8 \times y}{100}=(1860+20) \\ \Rightarrow 9 \mathrm{x}+8 \mathrm{y}=188000 \ldots \text { (ii) }
100 9×x + 100 8×y =(1860+20) ⇒9x+8y=188000… (ii)
Adding (i) and (ii), we get
⇒ x + y = 22000 …(iii)
On subtracting (i) and (ii), we get x – y = 2000 …(iv)
⇒ x = ₹12000
Now, x + y = 22000 [From (iii)]
⇒ y = 22000 – 12000 ⇒ y = 10,000
Hence, the amount invested in schemes A and B are 12000 and 10,000 respectively.
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Question 12 Susan invested certain amount of money in two schemes A and B, which offer interest at the rate of 8 % per annum and 9 % per annum, respectively. She received Rs. 1860 as annual interest. However, had she interchanged the amount of investments in the two schemes, she would have received Rs. 20 more as annual interest. How much money did she invest in each scheme?
Question 12 Susan invested certain amount of money in two schemes A and B, which offer interest at the rate of 8 % per annum and 9 % per annum, respectively. She received Rs. 1860 as annual interest. However, had she interchanged the amount of investments in the two schemes, she would have received Rs. 20 more as annual interest. How much money did she invest in each scheme?
Byju's Answer Standard IX Mathematics Compound Interest Question 12 S... Question Question 12
Susan invested certain amount of money in two schemes A and B, which offer interest at the rate of
8 % per annum and 9 %
per annum, respectively. She received Rs. 1860 as annual interest. However, had she interchanged the amount of investments in the two schemes, she would have received Rs. 20 more as annual interest. How much money did she invest in each scheme?
Open in App Solution
Let the amount of investments in schemes. A and B be Rs. x and Rs. y. respectively
Case I interest at the rate of
8 %
per annum on scheme A + interest at the rate of
9 %
percent annum on scheme B = Total amount received
⇒ x × 8 × 1 100 + y × 9 × 1 100 = R s .1860 [ ∴ s i m p l e i n t e r e s t = p r i n c i p l e × r a t e × t i m e 100 ] × 8 x + 9 y = 186000
Case II interest at the rate of
9 %
per annum on scheme A + interest at the rate of
8 %
per annum on scheme B = Rs. 20 more as annual interest
⇒ x × 9 × 1 100 + y × 8 × 1 100 = R s 20 + R s . 1860 ⇒ 9 x 100 + 8 y 100 = 1880 9x + 8y = 188000
On multiplying Eq. (i) by 9 and Eq. (ii) by 8 and then subtracting them, we get
72x + 81y = 9 × 186000 72x + 64y = 8 × 188000 ⇒ 17 y = 100 [ ( 9 × 186 ) − ( 8 × 188 ) ]
= 1000 (1674 – 1504) = 1000
× 170 17y = 170000 ⇒ y = 10000
On putting the value of y in Eq (i), we get
8x + 9 × 10000 = 186000 ⇒ 8x = 186000 – 90000 ⇒ 8x = 96000 ⇒ x = 12000
Hence, she invested Rs. 12000 and Rs. 10000 in two schemes A and B, respectively
Suggest Corrections 42
SIMILAR QUESTIONS
Q. Susan invested certain amount of money in two schemesA and B
, which offer interest at the rate of
8 % per annum and 9 %
per annum, respectively. She received Rs.
1860
as annual interest. However, had she interchanged the amount of investments in the two schemes, she would have received Rs.
20
more as annual interest. How much money did she invest in each scheme?
Q.Karan invested money in two schemes A and B offering compound interest at 8% per annum compounded annually and 9% per annum compounded annually. If the total amount of interest accrued through two schemes together in two years was Rs.4818.30 and the total amount invested was Rs.27,000, what was the amount invested in Scheme A?
Q. Sandeep invested Rs. 2500 in a scheme offering 20% per annum simple interest. Had he invested the same amount in another scheme offering 25% simple interest for two more years than the first scheme, he would have received Rs. 1500 more interest. Find the time period of investment in the second scheme.Q. A man invested an amount at 10% per annum and another amount at 8% per annum simple interest. Thus, he received ₹1,350 as annual interest. Had he interchanged the amounts invested, he would have received ₹45 less as interest. What amounts did he invest at different rates?Q.Babita invested a sum of money for 2 years at 4% per annum simple interest and earned Rs.480 as the interest.
How much more amount would she get if she had invested the same sum for the same time at the same rate compounded annually?
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