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    the area of circle that can be inscribed in a square of side 6 cm is

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    The area of the circle that can be inscribed in a square of side 6 cm is

    The area of the circle that can be inscribed in a square of side 6 cm is

    Byju's Answer Standard X Mathematics

    Areas of Different Plane Figures

    The area of t... Question

    The area of the circle that can be inscribed in a square of side 6 cm is __________.

    Open in App Solution

    If a circle is inscribed in a square, then the diameter of the circle is equal to the side of the square.

    Let the radius of the circle be r cm.

    Now,

    Diameter of the circle = Side of the square

    ⇒ 2r = 6 cm ⇒ r = 3 cm

    ∴ Area of the inscribed circle =πr2=π×32=9π cm2

    The area of the circle that can be inscribed in a square of side 6 cm is 9π cm2 .

    Suggest Corrections 39 SIMILAR QUESTIONS

    Q. Question 7

    The area of the circle that can be inscribed in a square of side 6 cm is

    (A) 36 π c m 2 (B) 18 π c m 2 (C) 12 π c m 2 (D) 9 π c m 2

    Q.

    Find the area of a square that can be inscribed in a circle of radius

    8 c m .

    Q. What is the area of the largest circle in sq. cm that can be inscribed in a square of side 14 cm?Q. What is the area of the circle in sq. cm that can be inscribed in a square of side 6 cm?Q. The area of the circle that can be inscribed in a square of side 10 cm is

    (a) 40 π cm2 (b) 30 π cm2 (c) 100 π cm2 (d) 25 π cm2 View More

    स्रोत : byjus.com

    The area of the circle that can be inscribed in a square of side 6 cm is

    Click here👆to get an answer to your question ✍️ The area of the circle that can be inscribed in a square of side 6 cm is

    Question

    The area of the circle that can be inscribed in a square of side 6 cm is

    A36 πcm

    2

    B18 πcm

    2

    C12 πcm

    2

    D9 πcm

    2 Medium Open in App Solution Verified by Toppr

    Correct option is D)

    Solution−

    Weknowthatthediameterofthecircleinscribedinasquare

    =onesideofthesquare.

    ∴PQ=onesideofthesquare=6cm.

    Sotheradiusr= 2 PQ ​ = 2 6 ​ cm=3cm. ∴Itsarea=πr 2 =π×3 2 cm 2 =9πcm 2 . Ans−Option−D.

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    स्रोत : www.toppr.com

    The area of the circle that can be inscribed in a square of side 6 cm is a. 36π cm², b. 18π cm², c. 12π cm², d. 9π cm²

    The area of the circle that can be inscribed in a square of side 6 cm is a. 36π cm², b. 18π cm², c. 12π cm², d. 9π cm² - The space occupied within the boundary/circumference of a circle is called the area of the circle

    The area of the circle that can be inscribed in a square of side 6 cm is

    a. 36π cm² b. 18π cm² c. 12π cm² d. 9π cm²

    Solution:

    Given, side of square = 6 cm

    We have to find the area of the circle that can be inscribed in the square.

    Diameter of circle = side of square = 6 cm

    Radius = 6/2 Radius = 3 cm

    Area of circle = πr²

    = π(3)² = 9π

    Therefore, the area of the circle is 9π square cm.

    ✦ Try This: The area of the square that can be inscribed in a circle of diameter 10 cm is

    Given, diameter of circle = 10 cm

    We have to find the area of the square that can be inscribed in the circle.

    Diameter of circle = diagonal of square.

    Area of square = (diagonal)²/2

    = (10)²/2 = 100/2 = 50 square cm.

    Therefore, the area of the square that can be inscribed in the circle of diameter 10 cm is 50 square cm.

    ☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 12NCERT Exemplar Class 10 Maths Exercise 11.1 Problem 7

    The area of the circle that can be inscribed in a square of side 6 cm is a. 36π cm², b. 18π cm², c. 12π cm², d. 9π cm²

    Summary:

    The space occupied within the boundary/circumference of a circle is called the area of the circle. The area of the circle that can be inscribed in a square of side 6 cm is 9π square cm

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    The radius of a circle whose circumference is equal to the sum of the circumferences of the two circ . . . .

    The diameter of a circle whose area is equal to the sum of the areas of the two circles of radii 24 . . . .

    स्रोत : www.cuemath.com

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