# the average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. what is the present age of the husband?

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## The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is:

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Question

## The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is:

**A**

## 35 years

**B**

## 40 years

**C**

## 50 years

**D**

## None of these

Medium Open in App Solution Verified by Toppr

Correct option is B)

Sum of the present ages of husband, wife and child =(27×3+3×3) years = 90 years.Sum of the present ages of wife and child =(20×2+5×2) years = 50 years.

∴ Husband's present age =(90−50) years =40 years.

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## Average General Questions

Discussion forum for Q. No. 8 of the Aptitude questions and answers section on "Average General Questions". Discussion Page 1 of 10, sorted by Newest.

## Aptitude :: Average - Discussion

Discussion Forum : Average - General Questions (Q.No. 8)

Average 8.

The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is:

35 years 40 years 50 years None of these Answer: Option Explanation:

Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.

Sum of the present ages of wife and child = (20 x 2 + 5 x 2) years = 50 years.

Husband's present age = (90 - 50) years = 40 years.

Discussion:

96 comments Page 1 of 10.

Rupesh Kumar Yadav said: 11 months ago

Sum of the present ages of H,W and C = 27 + 3 = 30 So, 30 * 3 = 90Years.

Sum of the present ages of H,W and C = 20 + 5 = 25 So, 25 * 2 = 50Years.

Hence,

Husband of presents age = (90-50)years.

= 40Years. (9) Ruthra said: 2 years ago

Wonderful explanation, thanks @Ramya.

Manoj Kumar said: 3 years ago

@Varshithtunuguntla.

How obtained here 90 and 40. How did the multiplication?

Can you tell me? Varshithtunuguntla said: 3 years ago

Your answer is correct. Thanks @Ramya.

Mayuri khode said: 3 years ago @Bharani.

Instead of addition W+C you can replace it by H+C.

i.e (H+W+C)-(H+C). Bharani said: 3 years ago

Same question but find the wife age means how to solve?

Sumit said: 3 years ago

The avg of age of your parents are 35 and avg of age of three of yours is 8 less. What is your age?

Please anyone answer this with explanation.

Anant gavas said: 3 years ago

(H+W+C)/3 = 27+3(add 3 to get present data).

H+W+C = 27*3+3*3 = 90.

(W+C)/2 = 20+5(to get present data).

W+C = 20*2+5*2 = 50.

So (H+W+C)-(W+C) = 40 years.

(6) Shasi kumar said: 3 years ago

Five years ago, the average age of the Ram family has 5 members including Ram was 29 years. Ram got married 3 years ago and his only child was born 2 years after marriage so that the present average age of family becomes 28 years. Find the age of a bride at the time of marriage?

(2) Sayed Sirajunnisa said: 3 years ago

A family of six members bought a car 10 years ago, and had a road accident today, in which one of the family members died. The average age of the family at the time when they bought the car is same as of today. What was the age of the member who passed away?can anyone help me with this problem, I need solution to this Question.

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## The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is

### Question Detail

## The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. The present age of the husband is

40 35 45 55

**Answer:**Option

**A**

**Explanation:**

Sum of the present ages of husband, wife and child = (27 * 3 + 3 * 3) years = 90 years.

Sum of the present ages of wife and child = (20 * 2 + 5 * 2) years = 50 years.

Husband's present age = (90 - 50) years = 40 years

Similar Questions :

## 1. The average of six numbers is X and the average of three of these is Y.If the average of the remaining three is z, then

x = y + z 2x = y + z x = 2y + z x = y + 2z

**Answer:**Option

**B**

**Explanation:**

X =((3y+3z)/6) or 2X= y + z

## 2. Average of all prime numbers between 30 to 50

37 37.8 39 39.8

**Answer:**Option

**D**

**Explanation:**

Prime numbers between 30 and 50 are:

31, 37, 41, 43, 47

Average of prime numbers between 30 to 50 will be

( 31+37+41+43+47 5 )= 199 5 =39.8

(31+37+41+43+475)=1995=39.8

## 3. Find the average of first 10 multiples of 7

35.5 37.5 38.5 40.5

**Answer:**Option

**C**

**Explanation:**

= 7(1+2+3+...+10) 10 =7(1+2+3+...+10)10 = 7(10(10+1)) 10×2 =7(10(10+1))10×2 = 7(110) 10×2 =38.5 =7(110)10×2=38.5

## 4. A library has an average of 510 visitors on Sundays and 240 on other day. The average number of visitors in a month of 30 days starting with sunday is

280 285 290 295

**Answer:**Option

**B**

**Explanation:**

As the month begin with sunday, so there will be five sundays in the month. So result will be:

=( 510×5+240×25 30 )=( 8550 30 )=285

=(510×5+240×2530)=(855030)=285

## 5. When a student weighing 45 kgs left a class, the average weight of the remaining 59 students increased by 200g. What is the average weight of the remaining 59 students

55 56 57 58

**Answer:**Option

**C**

**Explanation:**

Let the average weight of the 59 students be A.

So the total weight of the 59 of them will be 59*A.

The questions states that when the weight of this student who left is added, the total weight of the class = 59A + 45

When this student is also included, the average weight decreases by 0.2 kgs

59A+45 60 =A−0.2 59A+4560=A−0.2

=> 59A + 45 = 60A - 12

=> 45 + 12 = 60A - 59A

=> A = 57

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