the compounds formed upon combustion of sodium metal in excess air is
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The compound formed upon combustion of Na in excess air is
The compound formed upon combustion of Na in excess air is
Byju's Answer Standard XII Chemistry
Preparations and Reactions of Sodium Oxide
The compound ... Question
The compound formed upon combustion of Na in excess air is
A Na2O2 B Na2O C NaO2 D NaOH Open in App Solution
The correct option is B
Na2O 4 N a + 2 O 2 → 2 N a 2 O 2
In excess air it forms a peroxide.
4 N a + O 2 → 2 N a 2 O
In limited supply of air it forms sodium oxide.
Suggest Corrections 0 SIMILAR QUESTIONS
Q. The compound formed upon combustion of Na in excess air isQ.The compound(s) formed upon combustion of sodium metal in excess air is(are)
Q. The main oxides formed on the combustion ofL i , N a and K
in excess of air are, respectively:
Q. The compound(s) that can't be formed upon combustion of sodium metal in excess air is(are) :Q. The compound(s) formed upon combustion of sodium metal in excess air is/are(IIT-JEE, 2009)View More
The compound(s) formed upon combustion of sodium metal in the excess air is(are):
Click here👆to get an answer to your question ✍️ The compound(s) formed upon combustion of sodium metal in the excess air is(are):
Question
The compound(s) formed upon combustion of sodium metal in the excess air is(are):
This question has multiple correct options
ANa2 O 2
BNa2 O
CNaO2
DNaOH
Hard Open in App Solution Verified by Toppr
Correct options are A) and B)
The compound(s) formed upon the combustion of sodium metal in the excess air are sodium oxide and sodium peroxide.
The equation for the formation of the simple oxide is:
4Na+O 2 →2Na 2 O 2Na+O 2 →Na 2 O 2 Video Explanation
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15 1
The combustion of sodium in excess air yields a higher oxide. What is the oxidation state of the oxygen in the product?(Enter the magnitude value i.e. if the answer is $
The combustion of sodium in excess air yields a higher oxide. What is the oxidation state of the oxygen in the product?(Enter the magnitude value i.e. if the answer is $ - 2 $ enter $ 2 $ ). Ans: Hint: When the sodium metal is reacted with an exc...
The combustion of sodium in excess air yields a higher oxide. What is the oxidation state of the oxygen in the product?(Enter the magnitude value i.e. if the answer is
−2 −2 enter 2 2 ) Answer Verified 160.5k+ views
Hint: When the sodium metal is reacted with an excess amount of air or oxygen, it produces sodium peroxide. So we know it exists as sodium peroxide. So the oxidation number of oxygen will be−1 −1
. After entering the magnitude value it will change to
1 1
. For further explanation refer to the solution.
Complete answer:In ordinary air, sodium metal reacts to form a sodium hydroxide film, which can rapidly absorb carbon dioxide from the air, forming sodium bicarbonate. The temperature of burning sodium increases rapidly to more than
800 ∘ C 800∘C
, and under these conditions the fire is extremely difficult to extinguish.
4Na+ O 2 →2N a 2 O N a 2 O+ 1 2 O 2 →N a 2 O 2
4Na+O2→2Na2ONa2O+12O2→Na2O2
It exists as 2Na 2Na and O 2 −2 O2−2
. So, the oxidation state of
O O is −1 −1 .
The magnitude of a number (also called its absolute value) is its distance from zero, so. The magnitude of
6 6 is 6 6 . The magnitude of −6 −6 is also 6 6 . So, the answer is |−1|=1 |−1|=1 .
Note:Oxidation number, also called oxidation state, is the total number of electrons that an atom either gains or losses in order to form a chemical bond with another atom. The oxidation number of any free element has an oxidation number equal to zero. For monatomic ions, the oxidation number always has the same value as the net charge corresponding to the ion. The oxidation state of a free element (uncombined element) is zero.
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