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    the focal length of a biconvex lens with refractive index 1.5 and radius of curvature r on both sides is

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    The focal length of a biconvex lens is 20 cm and its refractive index is 1.5. If the radii of curvatures of two surfaces of lens are in the ratio 1 : 2, then the larger radius of curvature is :

    Click here👆to get an answer to your question ✍️ The focal length of a biconvex lens is 20 cm and its refractive index is 1.5. If the radii of curvatures of two surfaces of lens are in the ratio 1 : 2, then the larger radius of curvature is :

    Question

    The focal length of a biconvex lens is 20 cm and its refractive index is 1.5. If the radii of curvatures of two surfaces of lens are in the ratio 1 : 2, then the larger radius of curvature is :

    A

    10 cm

    B

    15 cm

    C

    20 cm

    D

    30 cm

    Medium Open in App Solution Verified by Toppr

    Correct option is D)

    From lens maker's formula,

    f 1 ​ =(μ−1)( R 1 ​ 1 ​ − R 2 ​ 1 ​ ) 20 1 ​ =(1.5−1)( R 1 ​ − (−2R) 1 ​ ) 20 1 ​ = 2 1 ​ × 2R 3 ​ R=15cm

    ∴  length of  radius =(2R)=2×15 cm=30 cm

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    The focal length of a biconvex lens is 20 cm and its refractive index is 1.5. If the radii of curvatures of two surfaces of lens are in the ratio 1:2, then the larger radius of curvature is (in cm)

    1/f=(mu-1)(1/R(1) - 1/R(2))The focal length of a biconvex lens is 20 cm and its refractive index is 1.5. If the radii of curvatures of two surfaces of lens are in the ratio 1:2, then the larger radius of curvature is (in cm)

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    The focal length of a biconvex...

    The focal length of a biconvex lens is 20 cm and its refractive index is 1.5. If the radii of curvatures of two surfaces of lens are in the ratio 1:2, then the larger radius of curvature is (in cm)

    Updated On: 17-04-2022

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    Text Solution A 10 B 15 C 20 D 30 Answer D Solution

    `1/f=(mu-1)(1/R_(1) - 1/R_(2))`

    Answer

    Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

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    FAQs on Ray Optics And Optical Instrauments

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    Why is the focal length of a convex lens equal to the radius of curvature when the refractive index is 1.5?

    Answer: That isn’t necessarily true. The focal length of an optical surface is given by this equation: f=R/(n'-n) , where R is the radius of curvature; n’ is index of refraction for the glass; and n’ is the index of refraction for the incident light ray’s medium. f is only equal to R when n'-n=1.

    Why is the focal length of a convex lens equal to the radius of curvature when the refractive index is 1.5?

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    1 Answer Robin Seibel

    , studied at Northmont High School

    Answered 3 years ago

    That isn’t necessarily true.

    The focal length of an optical surface is given by this equation:

    f=R/( n ′ −n) f=R/(n′−n)

    , where R is the radius of curvature; n’ is index of refraction for the glass; and n’ is the index of refraction for the incident light ray’s medium. f is only equal to R when

    n ′ −n=1. n′−n=1.

    3.5K viewsView upvotes

    Related answers Related Answer Harshit Rautela

    , studied Bachelor of Science in Computer Science & Photography at University of Delhi (2022)

    Updated 1 year ago · Author has 90 answers and 74.8K answer views

    Why is the focal length of a convex lens always positive?

    OK, many answers given here on the basis of image formation on the right side of the optical center and only sign convention are WRONG.

    Think about this, focal length is intrinsic property of a lens, and should not depend on how far the object or image is, though which side of lens they are on is important, which you’ll see why later in this answer.

    and And, this answer is particularly more difficult to comprehend, so either read carefully, or, skip to the last line.

    ALSO, FOCAL LENGTH OF A CONVEX OF A CONVEX LENS IS NOT ALWAYS POSITIVE, ESPECIALLY IF THE OBJECT IS ON THE RIGHT OF THE LENS .

    (whic Related Answer Steph Groom

    , former Structural Engineer and Project Manager (1980-2010)

    Answered 2 years ago · Author has 22.1K answers and 8.5M answer views

    The radius of curvature of the double convex lens are 10cm & 15cm. If the focal length is 12cm, what is the refractive index?

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    Related Answer Manickam N

    , retired teacher (1977-present)

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    Under what conditions will the radius of the curvature of a convex lens be equal to its focal length?

    When the refractive index is equal to 1.5, the focal length of a convex lens is equal to its radius of curvatures.

    f=r1=r2 Related Answer Bill Otto

    , studied Physics & Chemistry at The University of Alabama in Huntsville (1976)

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    How can a lens have two different radii of curvature but the same focal length? I thought the focal length is half of the radius of curvature, or is it only for curved mirrors and not lenses?

    Originally Answered: How can a lens have two different radii of curvature but the same focal length i thought focal length is half radius of curvature or is it only for curved mirrors only and not lenses?

    A lens is a little more complicated than a mirror.

    A mirror behaves mathematically as if the index were -1 and it only has one relevant surface.

    A lens has two surfaces, distance between them, and a refractive index, and all of those properties affect the focal length.

    The formula for the focal length of a lens in a vacuum is given by:

    1 f =(n−1)[ 1 R 1 − 1 R 2 + (n−1)d n R 1 R 2 ]

    1f=(n−1)[1R1−1R2+(n−1)dnR1R2]

    where

    f is the focal length

    R 1 R1

    is the radius of curvature of the first surface

    R 2 R2

    is the radius of curvature of the second surface

    n is the index of refraction of the lens

    d is Related Answer Chinmay Gaidhani

    Answered 5 years ago

    What is the relation between refractive index and focal length of a lens?

    1/f = (r.i -1)(1/R1-1/R2)

    R1 - radius of curvature of 1st surface

    R2 - radius of curvature of 2 nd surface

    r.i - Refractive Index

    f - focal length Related Answer Soutrik Das

    , Made some appscript as a freelancer

    Answered 1 year ago · Author has 78 answers and 155.5K answer views

    In a plano-convex lens the radius of curvature of the convex surface is 10 cm and the focal length of the lens is 30 cm. What will be the refractive index of the material of the lens?

    Lens Makers formula says that

    1 f =(μ−1)( 1 R 1 − 1 R 2 ) 1f=(μ−1)(1R1−1R2) So putting f=30cm f=30cm , R 1 =∞ R1=∞ and R 2 =−10cm R2=−10cm we get that μ= 4 3 μ=43

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    Related Answer Vinod Gohel

    , former Retired professor of physics at Gujarat University (1962-2003)

    स्रोत : www.quora.com

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