# the following distribution shows the daily pocket allowance of children of a locality

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## The following distribution shows the daily pocket allowance of children of a locality, The mean pocket allowance is Rs.18. Find the missing frequency f.Daily pocket Allowance (in Rs.)Number of children11

Click here👆to get an answer to your question ✍️ The following distribution shows the daily pocket allowance of children of a locality, The mean pocket allowance is Rs.18. Find the missing frequency f.Daily pocket Allowance (in Rs.)Number of children11 - 13713 - 15615 - 17917 - 191319 - 21f21 - 23523 - 254

The following distribution shows the daily pocket allowance of children of a locality, The mean pocket allowance is Rs.18. Find the missing frequency f.Question

Daily pocket Allowance (in Rs.)

Number of children 11-13 7 13-15 6 15-17 9 17-19 13 19-21 f 21-23 5 23-25 4

**A**

## f=10

**B**

## f=20

**C**

## f=15

**D**

## f=19

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## The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs 18. Find the missing frequency f.

The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs 18. Find the missing frequency f. - Get the answer to this question and access a vast question bank that is tailored for students.

Academic QuestionsMaths Questionsthe following distribution shows the daily pocket allowance of children of a locality the mean pocket allowance is rs 18 find the missing frequency f

## The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs 18. Find the missing frequency f.

**Daily Pocket Allowance(in c)**

**11-13**

**13-15**

**15-17**

**17-19**

**19-21**

**21-23**

**23-35**

**Number of children**

**7**

**6**

**9**

**13**

**f**

**5**

**4**

**Solution**

To determinet the missing frequency, we will use the mean formula.

Here, the value of mid-point (xi) mean x̄ = 18

**Class interval**

**Number of children (fi)**

**Mid-point (xi)**

**fixi**

11-13 7 12 84 13-15 6 14 84 15-17 9 16 144 17-19 13 18 = A 234 19-21 f 20 20f 21-23 5 22 110 23-25 4 24 96

Total fi = 44+f Sum fixi = 752+20f

**Formula**

The mean formula is

Mean = x̄ = ∑fixi /∑fi

= (752+20f)/(44+f)

On substituting the known values we get

⇒ 18 = (752 + 20f)/(44 + f)

⇒ 18(44 + f) = (752 + 20f)

⇒ 792 + 18f = 752 + 20f

⇒ 792 + 18f = 752 + 20f

⇒ 792 – 752 = 20f – 18f

⇒ 40 = 2f ⇒ f = 20

**Answer**

Hence, the missing frequency, f = 20.

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## Ex 14.1, 3

Ex 14.1, 3 The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs.18. Find the missing frequency f. Mean(𝑥 ̅) = a + (∑▒𝒇𝒊𝒅𝒊)/(∑▒𝒇𝒊) Where a = Assumed Mean h = Class interval = 18 = 13 – 11 = 2 Putting values in formula Mean

## Ex 14.1, 3 - Chapter 14 Class 10 Statistics (Term 2)

Last updated at May 12, 2021 by Teachoo

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