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    the following distribution shows the daily pocket allowance of children of a locality

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    The following distribution shows the daily pocket allowance of children of a locality, The mean pocket allowance is Rs.18. Find the missing frequency f.Daily pocket Allowance (in Rs.)Number of children11

    Click here👆to get an answer to your question ✍️ The following distribution shows the daily pocket allowance of children of a locality, The mean pocket allowance is Rs.18. Find the missing frequency f.Daily pocket Allowance (in Rs.)Number of children11 - 13713 - 15615 - 17917 - 191319 - 21f21 - 23523 - 254

    The following distribution shows the daily pocket allowance of children of a locality, The mean pocket allowance is Rs.18. Find the missing frequency f.

    Question

    Daily pocket Allowance (in Rs.)

    Number of children 11-13 7 13-15 6 15-17 9 17-19 13 19-21 f 21-23 5 23-25 4

    A

    f=10

    B

    f=20

    C

    f=15

    D

    f=19

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    स्रोत : www.toppr.com

    The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs 18. Find the missing frequency f.

    The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs 18. Find the missing frequency f. - Get the answer to this question and access a vast question bank that is tailored for students.

    Academic QuestionsMaths Questionsthe following distribution shows the daily pocket allowance of children of a locality the mean pocket allowance is rs 18 find the missing frequency f

    The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs 18. Find the missing frequency f.

    Daily Pocket Allowance(in c) 11-13 13-15 15-17 17-19 19-21 21-23 23-35Number of children 7 6 9 13 f 5 4Solution

    To determinet the missing frequency, we will use the mean formula.

    Here, the value of mid-point (xi) mean x̄ = 18

    Class interval Number of children (fi) Mid-point (xi) fixi

    11-13 7 12 84 13-15 6 14 84 15-17 9 16 144 17-19 13 18 = A 234 19-21 f 20 20f 21-23 5 22 110 23-25 4 24 96

    Total fi = 44+f Sum fixi = 752+20f

    Formula

    The mean formula is

    Mean = x̄ = ∑fixi /∑fi

    = (752+20f)/(44+f)

    On substituting the known values we get

    ⇒ 18 = (752 + 20f)/(44 + f)

    ⇒ 18(44 + f) = (752 + 20f)

    ⇒ 792 + 18f = 752 + 20f

    ⇒ 792 + 18f = 752 + 20f

    ⇒ 792 – 752 = 20f – 18f

    ⇒ 40 = 2f ⇒ f = 20

    Answer

    Hence, the missing frequency, f = 20.

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    Ex 14.1, 3

    Ex 14.1, 3 The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs.18. Find the missing frequency f. Mean(𝑥 ̅) = a + (∑▒𝒇𝒊𝒅𝒊)/(∑▒𝒇𝒊) Where a = Assumed Mean h = Class interval = 18 = 13 – 11 = 2 Putting values in formula Mean

    Ex 14.1, 3 - Chapter 14 Class 10 Statistics (Term 2)

    Last updated at May 12, 2021 by Teachoo

    स्रोत : www.teachoo.com

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