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    the marks obtained by 110 students in an examination are given below marks 30-35 35-40 40-45 45-50 50-55 55-60 60-65 number of students 14 16 28 23 18 8 3 find the mean marks of the students.

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    get the marks obtained by 110 students in an examination are given below marks 30-35 35-40 40-45 45-50 50-55 55-60 60-65 number of students 14 16 28 23 18 8 3 find the mean marks of the students. from screen.

    The marks obtained by 110 students in an examination are given below : Marks: 30

    The marks obtained by 110 students in an examination are given below : Marks: 30-35 35-40 40-45 45-50 50-55 55-60 60-65 Number of Students: 14 16 28 23 18 8 3 Find the mean marks of the students.

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    The marks obtained by 110 students in an examination are given below : Marks: 30-35

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    The marks obtained by 110 students in an examination are given below :

    Marks: 30-35 35-40 40-45 45-50 50-55 55-60 60-65

    Number of Students: 14 16 28 23 18 8 3

    Find the mean marks of the students.

    xi 32.5 37.5 42.5 47.5 52.5 57.5 62.5

    fi 14 16 28 23 18 8 3

    ui -3 -2 -1 0 1 2 3

    fiui -48 -32 -28 0 18 16 9

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    The marks obtained by 110 students in an examination are given below:[ Marks: 30 35 35 40 40 45 45 50 50 55 55 60 60 65 ]Frequency: 14 [ 16 28 23 18 8 3 ]Find the mean marks of the students.

    The marks obtained by 110 students in an examination are given below:[ Marks: 30 35 35 40 40 45 45 50 50 55 55 60 60 65 ]Frequency: 14 [ 16 28 23 18 8 3 ]Find the mean marks of the students.

    Byju's Answer Standard X Mathematics

    Direct Method of Finding Mean

    The marks obt... Question

    The marks obtained by 110 students in an examination are given below:

    Marks: 30 – 35 35 – 40 40 – 45 45 – 50 50 – 55 55 – 60 60 – 65

    Frequency: 14 16 28 23 18 8 3

    Find the mean marks of the students.

    Open in App Solution

    Let the assumed mean, A be 47.5.

    Here, h = 5

    Marks Mid-Values(xi) Frequency (fi)

    di=xi-47.5 ui=xi-47.55 fiui

    30–35 32.5 14 −15 −3 −42

    35–40 37.5 16 −10 −2 −32

    40–45 42.5 28 −5 −1 −28

    45–50 47.5 23 0 0 0

    50–55 52.5 18 5 1 18

    55–60 57.5 8 10 2 16

    60–65 62.5 3 15 3 9 ∑fi=110 ∑fiui=-59 We know Mean =A+h×∑fiui∑fi

    ∴ Mean marks of the students

    =47.5+5×-59110 =47.5-2.68 =44.82

    Hence, the mean marks of the students is 44.82.

    Suggest Corrections 43

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    स्रोत : byjus.com

    The marks obtained by 110 students in an examination are given below Marks 30

    The marks obtained by 110 students in an examination are given below Marks 30 3535 4040 4545 5050 5555 6060 65Frequency 141628231883 Find the mean marks of the students - Given:The marks obtained by 110 students in an examination.To do:We have to find the mean marks of the students.Solution:We know that,Mean $=frac{sum{f_ix_i}}{sum{f_i}}$    Therefore,  Mean $=frac{4930}{110}$$=frac{493}{11}$$=44.81$The mean marks of the students 44.81 marks.

    The marks obtained by 110 students in an examination are given below:Marks: 30-35 35-40 40-45 45-50 50-55 55-60 60-65Frequency: 14 16 28 23 18 8 3

    Find the mean marks of the students.

    AcademicMathematicsNCERTClass 10

    Given:

    The marks obtained by 110 students in an examination.

    To do:

    We have to find the mean marks of the students.

    Solution:

    We know that, Mean = ∑ f i x i ∑ f i =∑fixi∑fi Therefore, Mean = 4930 110 =4930110 = 493 11 =49311 =44.81 =44.81

    The mean marks of the students 44.81 marks.

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    Updated on 10-Oct-2022 10:52:42

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