the mean of the following frequency distribution is 57.6

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The mean of the following frequency distribution is 57.6 and the sum of all the frequencies is 50. Find the values of p and q.

Class intervals 0-20 20-40 40-60 60-80 80-100 100-120 Frequency 7 P 12 q 8 5 Solution: Class mark, xi = (upper class limit + lower class limit)/2 Class intervals Frequency fi Class mark xi fixi 0-20 7 10 70 20-40 P 30 30P 40-60 12 50 600 60-80 q 70 70q 80-100 8 90 720 100-120 […]

The mean of the following frequency distribution is 57.6 and the sum of all the frequencies is 50. Find the values of p and q.

CBSE | Class 10 | Exercise 1 | Maths | Measures of Central Tendency | ML Aggarwal

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The mean of the following frequency table is 57.6 . But the frequencies f1 and f2 are missing. Find the value of missing frequencies f1 and f2 .Class Interval 0

Click here👆to get an answer to your question ✍️ The mean of the following frequency table is 57.6 . But the frequencies f1 and f2 are missing. Find the value of missing frequencies f1 and f2 .Class Interval 0 - 20 20 - 40 40 - 60 60 - 80 80 - 100 100 - 120 TotalFrequency 7 f1 12 f2 8 5 50

The mean of the following frequency table is 57.6. But the frequencies f

Question 1 ​ and f 2 ​

are missing. Find the value of missing frequencies f

1 ​ and f 2 ​ .

Class Interval 0−20 20−40 40−60 60−80 80−100 100−120 Total

Frequency 7 f 1 ​ 12 f 2 ​ 8 5 50 Hard Open in App

Updated on : 2022-09-05

Solution Verified by Toppr

Class Interval     Frequency

( f)        Mid point x

fx 0−20 7 10 70 20−40 f 1 ​ 30 30f 1 ​ 40−60 12 50 600 60−80 f 2 ​ 70 70f 2 ​ 80−100 8 90 720 100−120 5 110 550 Total ∑f=32+f 2 ​ +f 2 ​ =50 ∑fx=30fx 1 ​ +70f 2 ​ +1940 ∑f=f 1 ​ +f 2 ​ +32=50 ⇒f 1 ​ +f 2 ​

=18           ..........(i)

Mean x ˉ = ∑f ∑fx ​ 57.6= 50 30f 1 ​ +70f 2 ​ +1940 ​ 30f 1 ​ +70f 2 ​ +1940=2,880 30f 1 ​ +70f 2 ​ =940 or 3f 1 ​ +7f 2 ​

=94             .............(ii)

Solving (i) and (ii)

f 1 ​ =8,f 2 ​ =10

Thus, the value of f

1 ​

is 8 and the value of f

2 ​ =10. Video Explanation

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Find the mean of the following frequency distribution is 57.6 and the total number of observations is 50. Find the missing frequencies f1 and f2.Class0 2020 4040 6060 8080 100100 120TotalFrequency7f112f28550

Find the mean of the following frequency distribution is 57.6 and the total number of observations is 50. Find the missing frequencies f1 and f2.Class0 2020 4040 6060 8080 100100 120TotalFrequency7f112f28550

Byju's Answer Standard VII History End of the Tughlaqs Find the mean... Question

Find the mean of the following frequency distribution is

57.6

and the total number of observations is

50

. Find the missing frequencies

f1 and f2 .

Class

0-20 20-40 40-60 60-80 80-100 100-120

TotalFrequency

7 f1 12 f2 8 5 50 Open in App Solution

Step 1 Finding mean:

The given table can be completed as below.

Class Frequency

(fi)

Mid values

(xi) (fixi) 0-20 7 10 70 20-40 f1 30 30f1 40-60 12 50 600 60-80 f2 70 1260-70f1 80-100 8 90 720 100-120 5 110 550

Total

∑fi=50 ∑(fixi)=3200-40f1

The formula for mean is

Mean(x¯) = ∑(fixi)∑fi

. where ∑fi

is the total frequency and

xi

is the mid-values of the class-intervals.

Mean is given as 57.6 .

The sum of frequencies is given as

50 . So,

⇒7+ f1 +12 + f2 + 8 + 5 =50

⇒ f1 + f2 = 18 ⇒f2 =18 - f1

Step 2 Finding values of

f1

and

f2

:

Apply the mean formula and substitute values,

⇒57.6=3200-40f150 ⇒40f1=320 ∴f1=8 Find the value of f2

by putting the value of

f1 in f2 =18 - f1 . ⇒f2 =18 - f1 ∴f2=10

Hence, the missing frequencies are

f1=8 and f2=10 . Suggest Corrections 5

SIMILAR QUESTIONS

Q. The mean of the following frequency distribution is 57.6 and the sum of the observations is 50

Class 0-20 20-40 40-60 60-80 80-100 100-120

Frequency 7 f1 12 f2 8 5

Q. Find the missing frequencies f1 and f2 in the table in given below, it is being given that the mean of the given frequency distribution is 50.

Class 0-20 20-40 40-60 60-80 80-100 Total

Frequency 17 f1 32 f2 19 120

Q. Q. Find the missing frequencies

f1,f2andf3

in the following frequency distribution, when it is given that

f2:f3

= 4 : 3, and mean = 50.

Class Interval Frequency

0-20 20-40 40-60 60-80 80-100 17 f1 f2 f3 19 Total 120

Q. If the median of the following frequency distribution is

46

. find the absolute difference of missing frequencies

Variable 10 − 20 20 − 30 30 − 40 40 − 50 50 − 60 60 − 70 70 − 80 Total Frequency 12 30 f 1 65 f 2 25 18 229

Q. If the mean of the following distribution be

50

, then find the values of

f 1 and f 2 .

Class 0-20 20-40 40-60 60-80 80-100 Total

Frequency 17 28 f 1 24 f 2 120 View More

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