# the radius of earth is about 6400 km and that of mars is 3200 km

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## The radius of earth is about 6400 km and that of Mars is 3200 km. The mass of the earth is about 10 times the mass of Mars. An object weighs 200 N on the surface of Earth. Its weight on the surface of mars will be:

Click here👆to get an answer to your question ✍️ The radius of earth is about 6400 km and that of Mars is 3200 km. The mass of the earth is about 10 times the mass of Mars. An object weighs 200 N on the surface of Earth. Its weight on the surface of mars will be:

Question

## The radius of earth is about 6400 km and that of Mars is 3200 km. The mass of the earth is about 10 times the mass of Mars. An object weighs 200 N on the surface of Earth. Its weight on the surface of mars will be:

**A**

## 20 N

**B**

## 8 N

**C**

## 80 N

**D**

## 40 N

Medium Open in App

Updated on : 2022-09-05

Solution Verified by Toppr

Correct option is C)

Radius of earth Re

=6400 and that of Mars is R

m =3200 so R e =2R m

And if mass of earth be M

e

and that of Mars is M

m then M e =10M m

Value of g on mars g

m = R m 2 GM m

and that on earth is g

e = R e 2 GM e = 4×R m 2 G×10M m =2.5 R m 2 GM m or g m =g e /2.5

Weight on earth is 200N so mass 200/g

e

Now weight on Mars will be mass×g

m =(200/g e )×g m =200× g e g m =200/2.5=80N

Option C is correct.

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## The radius of the earth is. 6400 km and that of mars is 3200 km. The mass of the earth is about 10 times the mass of mars. Weight of the object on the earth is 200 N.

The radius of the earth is. 6400 km and that of mars is 3200 km. The mass of the earth is about 10 times the mass of mars. Weight of the object on the earth is 200 N.

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The radius of the earth is. 6400 km and that of mars is 3200 km. The mass of the earth is about 10 times the mass of mars. Weight of the object on the earth is 200 N. What will be its weight on the mars?

### OPTIONS

100 N 40 N 200 N 80 N Advertisement Remove all ads

### SOLUTION

**80 N**

**Explanation:**

On Earth's surface g=GM1R12 On Mars's surface g=GM2R22

∴g′g=M2M1⋅R12R22=110(21)2

[∵R1R2=2] ∴g′g=410=0.4 g' = 0.4g

∴ mg' = 0.4mg = 0.4 × 200 = 80 N

Concept: Acceleration Due to Gravity (Earth’s Gravitational Acceleration)

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## The radius of earth is about 6400Km and that of mars is about 3200 km The mass of the earth is about 10times the mass of mars. An object weight 200N on earth 's surface, then its weight on the surface of mars will be:

g(E)=(GM)/(R^(2)) gM=(GM')/(R^(12))=(GM//10)/((R^(2))//4)=2/5(GM)/(R^(2))=2/5g(E) W(M)=W(E)=2/5=200xx2/5=80N

Home > English > Class 11 > Physics > Chapter > Gravitation >

The radius of earth is about 6...

The radius of earth is about

6400Km 6400Km

and that of mars is about

3200km 3200km

The mass of the earth is about

10 10

times the mass of mars. An object weight

200N 200N

on earth 's surface, then its weight on the surface of mars will be:

Updated On: 27-06-2022

00 : 38

UPLOAD PHOTO AND GET THE ANSWER NOW!

Text Solution Open Answer in App A 6N 6N B 20N 20N C 40N 40N D 80N 80N Answer

The correct Answer is D

Solution g E = GM R 2 gE=GMR2 gM= GM' R 12 = GM/10 ( R 2 )/4 = 2 5 GM R 2 = 2 5 g E

gM=GM′R12=GM/10(R2)/4=25GMR2=25gE

W M = W E = 2 5 =200× 2 5 =80N WM=WE=25=200×25=80N

Answer

Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

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Guys, does anyone know the answer?