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    the six digit number 54321a is divisible by 9 where a is a single digit whole number. find a

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    [Solved] If 54321A is divisible by 9, then find the value of 'A&#

    Given: 54321A is divisible by 9 Concept Used: Divisibility law of 9 ⇒ A number is divisible by 9 if the sum of its digit is divisible by 9. Calculation

    Home Quantitative Aptitude Number System Divisibility and Remainder

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    If 54321A is divisible by 9, then find the value of 'A'.

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    RRB JE Previous Paper 18 (Held On: 28 May 2019 Shift 1)

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    Answer (Detailed Solution Below)

    Option 3 : 3

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    RRB JE Previous Paper 1 (Held On: 22 May 2019 Shift 2)

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    Given:

    54321A is divisible by 9

    Concept Used:

    Divisibility law of 9 ⇒ A number is divisible by 9 if the sum of its digit is divisible by 9.

    Calculation:

    Sum of digits of 54321A = 5 + 4 + 3 + 2 + 1 + A

    ⇒ 15 + A If we put A = 3 ⇒ 15 + 3 ⇒ 18

    We know, 18 is divisible by 9.

    ∴ The required value of A is 3

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    A six digit number 54321A is divisible by 9 where A is a single digit whole number .Find A ​

    A six digit number 54321A is divisible by 9 where A is a single digit whole number .Find A​

    A six digit number 54321A is divisible by 9 where A is a single digit whole number .Find A ​

    Home/ Math/A six digit number 54321A is divisible by 9 where A is a single digit whole number .Find A ​

    A six digit number 54321A is divisible by 9 where A is a single digit whole number .Find A ​

    Question

    A six digit number 54321A is divisible by 9 where A is a single digit whole number .Find A

    ​ in progress 0 Math Aubrey 7 months 2 Answers 0 views 0

    Answers ( )

    Aubrey 0

    January 8, 2022 at 6:19 am

    Reply

    Answer:

    3 is the answer. for the given problem

    Step-by-step explanation:

    Given six digit number = 54321A

    A number is divisible by 9, if the sum of all the digits in the given number is divisible by 9.

    Sum of the digits = 5+4+3+2+1+A

    = 15+A

    So,The multiple of 9 after 15 is 18.

    therefore the value of A must be 3

    Now ,sum of the digits = 5+4+3+2+1+3=18

    18 is divisible by 9

    543213 is also divisible by 9

    Aubrey 0

    January 8, 2022 at 6:19 am

    Reply

    Answer:

    gkfuvfjfhdhfgytdcuf

    Leave An Answer

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    I am a mathematics educator with over 30 years’ experience teaching mathematics at the elementary, middle school, high school, and community college levels. I have master’s degree in mathematics education from the University of Michigan-Ann Arbor. In another lifetime, I earned a master’s in English from the University of Florida.

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    Mohammed 4 month ago
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