two pipes a and b can fill a cistern in 10 hours and 12 hours respectively and another two pipes c and d can empty a cistern in 6 hours and 5 hours respectively, find the time taken by them to empty half the cistern if all the pipes are operated simultaneously.
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get two pipes a and b can fill a cistern in 10 hours and 12 hours respectively and another two pipes c and d can empty a cistern in 6 hours and 5 hours respectively, find the time taken by them to empty half the cistern if all the pipes are operated simultaneously. from screen.
Two pipes A and B together can fill a cistern in 4 hours. Had they been opened separately, then B would have taken 6 hours more than A to fill the cistern. How much time will be taken by A to fill the cistern separately?
Click here👆to get an answer to your question ✍️ Two pipes A and B together can fill a cistern in 4 hours. Had they been opened separately, then B would have taken 6 hours more than A to fill the cistern. How much time will be taken by A to fill the cistern separately?
Question
Two pipes A and B together can fill a cistern in 4 hours. Had they been opened separately, then B would have taken 6 hours more than A to fill the cistern. How much time will be taken by A to fill the cistern separately?
A1 hour
B2 hours
C6 hours
D8 hours
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Updated on : 2022-09-05
Solution Verified by Toppr
Correct option is C)
Let the cistern be filled by pipe A alone in x hours.Then, pipe B will fit it in (x+6) hours.
∴ x 1 + (x+6) 1 = 4 1 ⇒ x(x+6) x+6+x = 4 1 ⇒x 2 −2x−24=0 ⇒(x−6)(x+4)=0
⇒x=6. [neglecting the negative value of x]
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[Solved] Two pipes A and B can fill an empty tank in 10 hours and 16
Given: Pipe A fills the empty tank in 10 hours Pipe B fills the empty tank in 16 hours Concept Used: Total work = LCM of time taken by each pipe Calculatio
Home Quantitative Aptitude Time and Work Pipe and Cistern
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Two pipes A and B can fill an empty tank in 10 hours and 16 hours respectively. They are opened alternately for 1 hour each, opening pipe B first, in how many hours, will the empty tank be filled?
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SSC CGL 2020 Tier-I Official Paper 14 (Held On : 20 Aug 2021 Shift 2)
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1425 1625 1025 1225
Answer (Detailed Solution Below)
Option 4 : 1225
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Given:Pipe A fills the empty tank in 10 hours
Pipe B fills the empty tank in 16 hours
Concept Used:Total work = LCM of time taken by each pipe
Calculation:LCM of 16 and 10 = 80
Let total work be 80 units
Pipe A does = 80/10 = 8 units per hour
Pipe B does = 80/16 = 5 units per hour
Now,
Pipe B & A fill the tank in two hour
⇒ (5 + 8) units ⇒ 13 units Now,
Each B & A will keep filling the tank for = (80/13) ≈ 6 hours
After (6 × 2) = 12 hours, the tank will be filled by (13 × 6) = 78 units.
2 units are yet to be filled
On, 13th hour B will be opened.
It will take 2/5 hour for B to fill the remaining tank entirely.
Total time = 12 + 2/5 =
∴ The empty tank will be filled in1225 hours 1225 hours.
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Two pipes X and Y can fill a c...
Two pipes X and Y can fill a cistern in 6 hours and 10 hours respectively. Pipe Z can empty the tank in 4 hours. If all the three pipes are open then in how many hours the cistern will be full?
Updated On: 27-06-2022
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Text Solution Open Answer in App A 30 B 45 C 50 D 60 Answer
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Guys, does anyone know the answer?