# two resistances r1 and r2 are connected with a cell in parallel. find the ratio of current flowing through r1 to the current flowing through r2.

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## The resistance R1 and R2 are joined in parallel and a current is passed so that the amount of heat liberated is H1 and H2 respectively. The ratio H1H2 has the value

Click here👆to get an answer to your question ✍️ The resistance R1 and R2 are joined in parallel and a current is passed so that the amount of heat liberated is H1 and H2 respectively. The ratio H1H2 has the value

The resistance RQuestion 1 and R 2

are joined in parallel and a current is passed so that the amount of heat liberated is H

1 and H 2

respectively. The ratio

H 2 H 1 has the value

**A**

R 1 R 2

**B**

R 2 R 1

**C**

R 2 2 R 1 2

**D**

R 1 2 R 2 2 Easy Open in App

Updated on : 2022-09-05

Solution Verified by Toppr

Correct option is A)

Heat produced, H=R V 2 t

both resistances are connected in parallel combination that's why both will get equal voltage drop hence heat produced will directly depend upon resitance value of them.

i.e. H∝ R 1 so H 2 H 1 = R 1 R 2

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## Two resistances R1 and R 2 are connected with a cell in parallel.

Two resistances R1 and R 2 are connected with a cell in parallel. Find the ratio of current flowing through R1 to the current flowing through R2.

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## Two resistances R1 and R 2 are connected with a cell in parallel. Find the ratio of current flowing through R1 to the current flowing through R2.

Related Answer

Two resistance R1 and R2 connected in parallel, this equivalent resistance is.

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Question

The two resistance R1 and R2 are connected in series. The current flowing through these two is___.

Open in App Solution

**Step 1:**Equivalent resistance for series combination

The formula to find the equivalent resistance is given by,

Req=R1+R2

**Step 2:**Current flowing through the resistance

The relation to finding the current is given by,

I=V12Req

Here, V12 is the voltage difference between the two resistance.

Substitute the values in the above relation.

I=V12R1+R2

Thus, the current flowing through the two resistances is I=V12R1+R2.

Series and Parallel Combination of Resistors

Standard XII Physics

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