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# two resistances r1 and r2 are connected with a cell in parallel. find the ratio of current flowing through r1 to the current flowing through r2.

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### Mohammed

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## The resistance R1 and R2 are joined in parallel and a current is passed so that the amount of heat liberated is H1 and H2 respectively. The ratio H1H2 has the value

Click here👆to get an answer to your question ✍️ The resistance R1 and R2 are joined in parallel and a current is passed so that the amount of heat liberated is H1 and H2 respectively. The ratio H1H2 has the value

The resistance R

Question 1 ​ and R 2 ​

are joined in parallel and a current is passed so that the amount of heat liberated is H

1 ​ and H 2 ​

respectively. The ratio

H 2 ​ H 1 ​ ​ has the value

A

R 1 ​ R 2 ​ ​

B

R 2 ​ R 1 ​ ​

C

R 2 2 ​ R 1 2 ​ ​

D

R 1 2 ​ R 2 2 ​ ​ Easy Open in App

Updated on : 2022-09-05

Solution Verified by Toppr

Correct option is A)

Heat produced, H=

R V 2 t ​

both resistances are connected in parallel combination that's why both will get equal voltage drop hence heat produced will directly depend upon resitance value of them.

i.e. H∝ R 1 ​ so H 2 ​ H 1 ​ ​ = R 1 ​ R 2 ​ ​

12 7

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## Two resistances R1 and R 2 are connected with a cell in parallel.

Two resistances R1 and R 2 are connected with a cell in parallel. Find the ratio of current flowing through R1 to the current flowing through R2.

Question : Next Question

## Two resistances R1 and R 2 are connected with a cell in parallel. Find the ratio of current flowing through R1 to the current flowing through R2.

Two resistance R1 and R2 connected in parallel, this equivalent resistance is.

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Question

The two resistance R1 and R2 are connected in series. The current flowing through these two is___.

Open in App Solution

Step 1: Equivalent resistance for series combination

The formula to find the equivalent resistance is given by,

Req=R1+R2

Step 2: Current flowing through the resistance

The relation to finding the current is given by,

I=V12Req

Here, V12 is the voltage difference between the two resistance.

Substitute the values in the above relation.

I=V12R1+R2

Thus, the current flowing through the two resistances is I=V12R1+R2.

Series and Parallel Combination of Resistors

Standard XII Physics

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Mohammed 4 day ago

Guys, does anyone know the answer?