# two unbiased coins are tossed. evaluate probability of getting at most two head?

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## Two unbiased coins are tossed simultaneously. The probability of getting two heads

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Question

## Two unbiased coins are tossed simultaneously. The probability of getting two heads

**A**

2 1

**B**

4 1

**C**

4 3

**D**

## None

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Updated on : 2022-09-05

Solution Verified by Toppr

Correct option is B)

Favourable number of outcomes, getting two heads = 1 i.e {HH}Total number of outcomes =6 i.e {HH, HT, TH, TT}

Probability = 4 1

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## Two unbiased coins are tossed simultaneously. What is the probability of two heads?

Answer (1 of 8): Total number of possibilities when 2 coins are tossed is 2^2=4 viz (H,H),(H,T),(T,H),(T,T). And out of these there is only one possibility of getting both heads i.e (H,H) Hence, the required probability is \frac{1}{4}

Two unbiased coins are tossed simultaneously. What is the probability of two heads?

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Sort Abdul Quddoos

Assistant Professor at Integral University (2016–present)2y

S= {HH, HT, TH, TT) P(Two heads)= 1/4 Related questions

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Parag Kalita

Interested in numbers.Author has 175 answers and 611.4K answer views2y

Coins are unbiased, so the probability of getting head or tail is 1/2.

S= { (H,H),(H,T),(T,H),(T,T) }

n(S)= 4

Let, A is the set of getting two heads.

A= { (H,H) } n(A)= 1

so, the probability is P(A)= n(A)/n(S) = 1/4.

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Likhitha Dulla

StudentAuthor has 121 answers and 87.5K answer views2y

When 2 unbiased coins are tossed, the no.of possible outcomes are 4 and they are:—

Head, Head Head, Tail Tail, Head Tail, Tail

Probability of an event =

no.of favourable outcomes of the event/total no.of outcomes

Here the no.of favourable outcomes of the event is 1

So P(2 heads)=1/4 =0.25

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Absolutely not Definitely yes Jitendra Sikarwar

Bsc from St. Johns' College, Agra2y

If two coins are tossed simultaneously the the total outcomes is 2^no. of coins

=2^2=>4

{(H,H), (H,T), (T,H), (T,T)} they are rhe total outcomes

Probability= (favourable outcome) / (total outcomes)

(H,H) is comes one time so ,

1/4 is the probability of two heads.

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Jay Modi

Lives in SolitudeAuthor has 62 answers and 67.9K answer views2y

Answer is 1/4. Possible Outcomes 1. H,H 2. H,T 3. T,H 4. T,T

So there are total 4 possibilities.

Probability = 2 Heads as Outcome/Total number of outcome = 1/4

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Sheik Meer Mohiuddin

Lecturer in Maths (1998–present)2y

Two unbiased coins are tossed total number of outcomes = 4 (HH HT TH TT )

Event of getting two heads =1. (HH)

PROBABILITY = 1/4 Robert Nichols

Author has 4.9K answers and 10.9M answer views4y

Related

If four coins are tossed simultaneously, what are the possible outcomes?

I like to start with a tree diagram:

There are 16 equally likely outcomes:

HHHH HHHT HHTH HHTT HTHH HTHT HTTH HTTT

THHH THHT THTH THTT TTHH TTHT TTTH TTTT

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Partha Chattopadhyay

Taught while teaching and still practicingAuthor has 3.6K answers and 5.3M answer views2y

Total number of possibilities when 2 coins are tossed is

2 2 =4 22=4 viz

(H,H),(H,T),(T,H),(T,T).

(H,H),(H,T),(T,H),(T,T).

And out of these there is only one possibility of getting both heads i.e

(H,H) (H,H)

Hence, the required probability is

1 4 14 Raman Singh

Superintendent of Customs at Customs House,Chennai at Central Board of Excise and Customs (2020–present)Author has 165 answers and 118.2K answer views2y

If we denote a Heads & a Tails by H & T, respectively, then the total possible outcomes are 4 ( HH, HT, TH & TT )

Hence, required Probability is 1/4.

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## Two unbiased coins are tossed simultaneously. Find the probability of gettingi. two headsii. one tailiii. at least one tailiv. at most one tailv. no tail

Two unbiased coins are tossed simultaneously. Find the probability of gettingi. two headsii. one tailiii. at least one tailiv. at most one tailv. no tail. Ans: Hint- In order to solve such type of question we must use formula Probability \\[\\left( {...

Two unbiased coins are tossed simultaneously. Find the probability of gettingi. two heads ii. one tail

iii. at least one tail

iv. at most one tail

v. no tail Answer Verified 170.6k+ views

Hint- In order to solve such type of question we must use formula Probability

(P) =

Favourable number of cases

Total number of cases

(P) = Favourable number of casesTotal number of cases

, along with proper understanding of favourable cases and total cases.

Complete step-by-step answer:

If two unbiased coins are tossed simultaneously, then the total number of possible outcomes may be either.

1.both head HH

2.one head and one tail (HT, TH)

3.Both tail (TT)

So here total number of possible cases = 4

(i) two heads

a favourable outcome for two heads is HH.

No. of favourable outcomes = 1

total number of possible cases = 4

As we know that Probability

(P) =

Favourable number of cases

Total number of cases

(P) = Favourable number of casesTotal number of cases

Probability (two heads) =

1 4 14

(ii) favourable outcomes for one tail are TH, HT.

No. of favourable outcomes = 2

total number of possible cases = 4

As we know that Probability

(P) =

Favourable number of cases

Total number of cases

(P) = Favourable number of casesTotal number of cases

Probability(one tail) =

2 4 = 1 2 24 = 12

(iii) favourable outcomes for at least one tail are TH, HT, TT.

No. of favourable outcomes = 3

total number of possible cases = 4

As we know that Probability

(P) =

Favourable number of cases

Total number of cases

(P) = Favourable number of casesTotal number of cases

Probability (at least one tail) =

3 4 34

(iv) Favourable outcomes for at least one head are TH, HT, HH.

No. of favourable outcomes = 3

total number of possible cases = 4

As we know that Probability

(P) =

Favourable number of cases

Total number of cases

(P) = Favourable number of casesTotal number of cases

Probability (at least one head) =

3 4 34

(v) favourable outcomes for no tail means not a single head is HH.

No. of favourable outcomes = 1

total number of possible cases = 4

As we know that Probability

(P) =

Favourable number of cases

Total number of cases

(P) = Favourable number of casesTotal number of cases

Probability(no tail) =

1 4 14

NOTE- In Such Types of Question first find out the total numbers of possible outcomes then find out the number of favourable cases, then divide them using the formula which stated above, we will get the required answer.

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