# we have a vessel containing 90 l of orange juice and 10 l of alcohol. out of this vessel, we pulled out 20 l of solution and changed it with water. this whole process was done two more times. now calculate the quantity of orange juice remaining in the vessel?

### Mohammed

Guys, does anyone know the answer?

get we have a vessel containing 90 l of orange juice and 10 l of alcohol. out of this vessel, we pulled out 20 l of solution and changed it with water. this whole process was done two more times. now calculate the quantity of orange juice remaining in the vessel? from screen.

## A container contains 100 L of milk. From this container 10 L of milk was taken out and replaced by water. This process was further repeated three times. How much milk does the container have now?

Click here👆to get an answer to your question ✍️ A container contains 100 L of milk. From this container 10 L of milk was taken out and replaced by water. This process was further repeated three times. How much milk does the container have now?

Question

## A container contains 100 L of milk. From this container 10 L of milk was taken out and replaced by water. This process was further repeated three times. How much milk does the container have now?

**A**

## 72.9 L

**B**

## 65.61 L

**C**

## 34.39 L3

**D**

## 81 L

Medium Open in App Solution Verified by Toppr

Correct option is B)

Final concentration = Initial concentration (1−Initial Replaced ) n =100(1− 100 10 )=100× 100 90 × 100 90 × 100 90 × 100 90 = 65.61 litres

Was this answer helpful?

37 17

## [Solved] A vessel contained 90 litre coca cola. Out of this 10 litre

GIVEN : Total quantity of coca cola = 90 litres Replace in a time = 10 litre Replacement process = 2 FORMULA USED : Final quantity = Initial quanti

Home Quantitative Aptitude Mixture Problems

## Question

Download Solution PDF

## A vessel contained 90 litre coca cola. Out of this 10 litre of coca cola was taken out and replaced with alcohol. This process was further repeated one more times. Find the approx. remaining quantity of coca cola in the vessel ?

76 72 70 74 75

## Answer (Detailed Solution Below)

Option 2 : 72

Crack SSC+Banking+Railways Combo Pass with

India's Super Teachers

FREE

Demo Classes Available*

Explore Supercoaching For FREE

**Free Tests**

View all Free tests >

FREE

Syllogism (Clear Your Basics)

1.2 Lakh Users

10 Questions 10 Marks 10 Mins

Start Now

## Detailed Solution

Download Solution PDF

**GIVEN :**

Total quantity of coca cola = 90 litres

Replace in a time = 10 litre

Replacement process = 2

**FORMULA USED :**

Final quantity = Initial quantity × (1 – Replacement part)T

Where

T → Replacement process

**CALCULATION :**

Total quantity coca cola = 90 litres

Part of replacement = 10/90 = 1/9 part

In First replacement

Quantity of coca cola which is taken out = 90 × 1/9 = 10 litre

Remaining coca cola = 90 – 10 = 80 litre

Quantity of alcohol = 9 litre

Ratio of coca cola and alcohol = 80 ∶ 10

⇒ 8 ∶ 1

In second replacement

Quantity of mixture which is taken out = 90 × 1/9 = 10 litre

In 10 litre quantity of coca cola which is taken out = (10/9) × 8 = 8.88

Remaining quantity of coca cola in the vessel = 80 – 8.88 = 71.11 ≈ 72 litre

**∴**

**After second replacement remaining quantity of coca cola is approx. 72 litre**

Replacement part = 10/90 = 1/9

Final quantity of juice = Initial quantity of juice × (1 – Replacement part)T

⇒ 90 × (1 – 1/9)2 ⇒ 90 × 64/81 ⇒ 71.11 ≈ 72 litre

**∴ After second replacement remaining quantity of coca cola is approx. 72 litre**

Download Solution PDF

Share on Whatsapp

Latest IBPS PO Updates

Last updated on Nov 2, 2022

**The IBPS PO Admit Card is released for the Mains Exam to be held on 26th November 2022.**Also, the mains exam pattern has been revised, check out the IBPS PO Mains Exam Pattern here.The Institute of Banking Personnel Selection (IBPS) had released the IBPS PO Prelims Result 2022. The exam was held on 15th and16th October 2022. The candidates who have cleared the prelims exam will be eligible to appear in the mains exam. The mains exam is tentatively scheduled on 26th November 2022. The selection process of the IBPS PO includes - Prelims, Mains, Interview. The selected candidates will get a salary of a pay scale from Rs. 23,700 to Rs. 42,020.

Get proficient with the Quantitative Aptitude concepts with detailed lessons on the topic Mixture Problems among many others.

India’s **#1 Learning** Platform

Start Complete Exam Preparation

Daily Live MasterClasses

Practice Question Bank

Mock Tests & Quizzes

Get Started for Free

Download App

Trusted by 3.5 Crore+ Students

‹‹ Previous Ques Next Ques ››

## More Mixture Problems Questions

**Q1.**A container contains 40 litres of milk. From this container 4 litres of milk was taken out and replaced by 4 litres of water. This process was repeated further two times. How much milk is left in the container ?

**Q2.**The ratio of milk to water in 80 litres of a mixture is 7 : 3. The water (in litres) to be added to it to make the ratio of milk to water 2 : 1 is

**Q3.**Tea worth ₹126 per kg and ₹135 per kg are mixed with a third variety of tea in the ratio 1 ∶ 1 ∶ 2. If the mixture is worth ₹153 per kg, the price of the third variety per kg is:

**Q4.**In 1 kg. mixture of sand and iron, 20% is iron. How much sand should be added so that the proportion of iron becomes 10% ?

**Q5.**8 litres are drawn from a cask full of wine and is then filled with water. This operation is performed three more times. The ratio of the quantity of wine now left in cask to that of the water is 16 ∶ 65 respectively. How much wine did the cask hold originally?

**Q6.**A container contains 40 litres of milk. From this container 4 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?

**Q7.**60 kg of an alloy A is mixed with 100 kg of alloy B. If alloy A has lead and tin in the ratio 3 ∶ 2 and alloy B has tin and copper in the ratio 1 ∶ 4, then the amount of tin in the new alloy is :

**Q8.**One quality of wheat at Rs. 9.30 per kg is mixed with another quality at a certain rate in the ratio 8 ∶ 7. If the mixture so formed be worth Rs. 10 per kg, what is the rate per kg of the second quality of wheat?

**Q9.**In what ratio must a grocer mix two varieties of tea worth Rs. 60 a kg and Rs. 65 a kg so that by selling the mixture at Rs. 68.20 a kg he may gain 10%?

## A container contains 50 litres of milk. From this container 5 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?

Answer (1 of 20): Initially, milk in the container = 50 Litres Water in the container = 0 L On removing 5L milk and adding same amount of water, Milk in the container = 45 L Water in the container = 5 L I hope, upto here, it's clear. When again same process is done, 5 L of the solution has b...

A container contains 50 litres of milk. From this container 5 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?

Sort Vasudevan A.N.S.

Former Retired Professor of Chemistry. (1977–2014)Author has 7.8K answers and 9.1M answer views2y

When we remove 5- litres of milk or Milk-water mixture, Everytime we remove 10% or the mixture is left with 90% of the milk Present in it.

So after three such operations, the amount of pure milk present in the mixture =

=50 0.9 x 0.9 x 0.9 = 36.45- litres

====================

Systematic Method is given by other authors.

But I have given a fast and simple method.

=====================

Related questions

A container has 50 litres of milk. From this 5 kg of milk was taken out & replaced by water. This process further repeated two times. How much milk is now contained by the container (in litres)?

A container contains 40 liters of milk. From this container 5 litres of milk was taken out and replaced by water. This process was repeated further two times. what milk is now contained by the container?

A container contained 60l milk. Out of this 6l of milk was taken out and replaced with water. This process was repeated two more times further. How much milk is now in container? (in litres)?

A container contains 70litre of milk. From this container 5 litre of milk was taken out and replaced by water. This process was repeated further two times. what is the quantity of milk left in the container?

A container contains 30 litres of milk. From this container 3 litres of milk was taken out and replaced by water. This process was repeated further two times. What milk is now contained by the container?

Rohann Ahuja

Teacher, Founder at R S COACHING (2016–present)2y

Since everytime 10% of the solution is removed

( For the first time it says 5 litre solution is removed from 50 litres milk so 5/50 * 100 = 10%)

And the process is repeated 3 times

So

50 *9/10 * 9/10 * 9/10

36.45 L milk is left in the solution

Linus Syngkli

Account andpublic financial management systemPFMSAuthor has 290 answers and 204.5K answer views2y

Remaining milk in container: (45*45*45)*50/(50*50*50)= 36.45 litre

Note: 50–5=45. Initial quantity of milk is 50

So when 5 liter is drawn out remaining is 45.

And 5 liter of water is added total is 50, so this process is repeated in another two time which mean all together is three time, so I repeated three time 45/50. Last process in mixture is 50 liter because after added 5 liter of water in mixture there is no taken out

Ayush Singh

B.Tech in Electronics and Communication Engineering, Vellore Institute of Technology, Chennai Campus (Expected 2023)2y

Initially, milk in the container = 50 Litres

Water in the container = 0 L

On removing 5L milk and adding same amount of water,

Milk in the container = 45 L

Water in the container = 5 L

I hope, upto here, it's clear. When again same process is done, 5 L of the solution has been taken out ( We can't say 5L milk will be taken out because that has become a solution now). So if 50 L solution has 45L milk and 5 L water, 5 L solution will have 4.5L milk and 0.5L water

So now, milk in the container = 45–4.5 = 40.5 L

Water in the container = 5–0.5+5 = 9.5 L

The sum of volumes of milk and water should be always

Related questions

A container contains 40 litres of milk. From this container, 4 litres of milk were taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?

A container contains 50 litres of milk. From that 8 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?

A shopkeeper has a vessel that contains 200 litres of milk. From this container, 20 litres of milk was taken out and replaced by water. This process is repeated two more times. How much milk is now left in the container?

A container has 70 L of milk. From this container, 10 L was taken out and replaced by water. The process was further repeated twice. What is the value of milk in the container after that?

A container contains 80 litres of milk. From this container 4 litres of milk was taken out and replaced by water. This process was repeated further two times. What milk is now contained by the container?

Deepa Chhatwani

Own Business at Independent Distributor (2003–present)Author has 728 answers and 104.1K answer views2y

Suppose a container contains X units of a liquid from which Y units are taken out and replaced by water.

After N operations, quantity of pure liquid = X ( 1 - Y / X ) ^ N units

Now, milk exist in the container is = 50 ( 1 - 5 / 50 ) ^ 3

= 50 ( 1 - 1 / 10 ) ^ 3

= 50 * 9/10 * 9/10 * 9/10

= ( 5 * 9 * 9 * 9 ) / 100

= 36.45 liters Naga Prabha

Former Central Govt OfficerAuthor has 1.2K answers and 143.6K answer views1y

status of milk and water in the beginning

m i l k : water total

50 L : 0 = 50

after 5 litres milk taken out and adding water

Milk : water = 45 L : 5 L = 9:1

again 5 litres milk taken out and 5 litres water added

Guys, does anyone know the answer?