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    we have a vessel containing 90 l of orange juice and 10 l of alcohol. out of this vessel, we pulled out 20 l of solution and changed it with water. this whole process was done two more times. now calculate the quantity of orange juice remaining in the vessel?

    Mohammed

    Guys, does anyone know the answer?

    get we have a vessel containing 90 l of orange juice and 10 l of alcohol. out of this vessel, we pulled out 20 l of solution and changed it with water. this whole process was done two more times. now calculate the quantity of orange juice remaining in the vessel? from screen.

    A container contains 100 L of milk. From this container 10 L of milk was taken out and replaced by water. This process was further repeated three times. How much milk does the container have now?

    Click here👆to get an answer to your question ✍️ A container contains 100 L of milk. From this container 10 L of milk was taken out and replaced by water. This process was further repeated three times. How much milk does the container have now?

    Question

    A container contains 100 L of milk. From this container 10 L of milk was taken out and replaced by water. This process was further repeated three times. How much milk does the container have now? 

    A

    72.9 L

    B

    65.61 L

    C

    34.39 L3

    D

    81 L

    Medium Open in App Solution Verified by Toppr

    Correct option is B)

    Final concentration = Initial concentration (1−

    Initial Replaced ​ ) n =100(1− 100 10 ​ )=100× 100 90 ​ × 100 90 ​ × 100 90 ​ × 100 90 ​ = 65.61 litres

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    स्रोत : www.toppr.com

    [Solved] A vessel contained 90 litre coca cola. Out of this 10 litre

    GIVEN : Total quantity of coca cola = 90 litres Replace in a time = 10 litre Replacement process = 2   FORMULA USED : Final quantity = Initial quanti

    Home Quantitative Aptitude Mixture Problems

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    A vessel contained 90 litre coca cola. Out of this 10 litre of coca cola was taken out and replaced with alcohol. This process was further repeated one more times. Find the approx. remaining quantity of coca cola in the vessel ?

    76 72 70 74 75

    Answer (Detailed Solution Below)

    Option 2 : 72

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    Detailed Solution

    Download Solution PDF

    GIVEN :

    Total quantity of coca cola = 90 litres

    Replace in a time = 10 litre

    Replacement process = 2

    FORMULA USED :

    Final quantity = Initial quantity × (1 – Replacement part)T

    Where

    T → Replacement process

    CALCULATION :

    Total quantity coca cola = 90 litres

    Part of replacement = 10/90 = 1/9 part

    In First replacement

    Quantity of coca cola which is taken out = 90 × 1/9 = 10 litre

    Remaining coca cola = 90 – 10 = 80 litre

    Quantity of alcohol = 9 litre

    Ratio of coca cola and alcohol = 80 ∶ 10

    ⇒ 8 ∶ 1

    In second replacement

    Quantity of mixture which is taken out = 90 × 1/9 = 10 litre

    In 10 litre quantity of coca cola which is taken out = (10/9) × 8 = 8.88

    Remaining quantity of coca cola in the vessel = 80 – 8.88 = 71.11 ≈ 72 litre

    After second replacement remaining quantity of coca cola is approx. 72 litre

    Replacement part = 10/90 = 1/9

    Final quantity of juice = Initial quantity of juice × (1 – Replacement part)T

    ⇒ 90 × (1 – 1/9)2 ⇒ 90 × 64/81 ⇒ 71.11 ≈ 72 litre

    ∴ After second replacement remaining quantity of coca cola is approx. 72 litre

    Download Solution PDF

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    More Mixture Problems Questions

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    स्रोत : testbook.com

    A container contains 50 litres of milk. From this container 5 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?

    Answer (1 of 20): Initially, milk in the container = 50 Litres Water in the container = 0 L On removing 5L milk and adding same amount of water, Milk in the container = 45 L Water in the container = 5 L I hope, upto here, it's clear. When again same process is done, 5 L of the solution has b...

    A container contains 50 litres of milk. From this container 5 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?

    Sort Vasudevan A.N.S.

    Former Retired Professor of Chemistry. (1977–2014)Author has 7.8K answers and 9.1M answer views2y

    When we remove 5- litres of milk or Milk-water mixture, Everytime we remove 10% or the mixture is left with 90% of the milk Present in it.

    So after three such operations, the amount of pure milk present in the mixture =

    =50 0.9 x 0.9 x 0.9 = 36.45- litres

    ====================

    Systematic Method is given by other authors.

    But I have given a fast and simple method.

    =====================

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    Rohann Ahuja

    Teacher, Founder at R S COACHING (2016–present)2y

    Since everytime 10% of the solution is removed

    ( For the first time it says 5 litre solution is removed from 50 litres milk so 5/50 * 100 = 10%)

    And the process is repeated 3 times

    So

    50 *9/10 * 9/10 * 9/10

    36.45 L milk is left in the solution

    Linus Syngkli

    Account andpublic financial management systemPFMSAuthor has 290 answers and 204.5K answer views2y

    Remaining milk in container: (45*45*45)*50/(50*50*50)= 36.45 litre

    Note: 50–5=45. Initial quantity of milk is 50

    So when 5 liter is drawn out remaining is 45.

    And 5 liter of water is added total is 50, so this process is repeated in another two time which mean all together is three time, so I repeated three time 45/50. Last process in mixture is 50 liter because after added 5 liter of water in mixture there is no taken out

    Ayush Singh

    B.Tech in Electronics and Communication Engineering, Vellore Institute of Technology, Chennai Campus (Expected 2023)2y

    Initially, milk in the container = 50 Litres

    Water in the container = 0 L

    On removing 5L milk and adding same amount of water,

    Milk in the container = 45 L

    Water in the container = 5 L

    I hope, upto here, it's clear. When again same process is done, 5 L of the solution has been taken out ( We can't say 5L milk will be taken out because that has become a solution now). So if 50 L solution has 45L milk and 5 L water, 5 L solution will have 4.5L milk and 0.5L water

    So now, milk in the container = 45–4.5 = 40.5 L

    Water in the container = 5–0.5+5 = 9.5 L

    The sum of volumes of milk and water should be always

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    Deepa Chhatwani

    Own Business at Independent Distributor (2003–present)Author has 728 answers and 104.1K answer views2y

    Suppose a container contains X units of a liquid from which Y units are taken out and replaced by water.

    After N operations, quantity of pure liquid = X ( 1 - Y / X ) ^ N units

    Now, milk exist in the container is = 50 ( 1 - 5 / 50 ) ^ 3

    = 50 ( 1 - 1 / 10 ) ^ 3

    = 50 * 9/10 * 9/10 * 9/10

    = ( 5 * 9 * 9 * 9 ) / 100

    = 36.45 liters Naga Prabha

    Former Central Govt OfficerAuthor has 1.2K answers and 143.6K answer views1y

    status of milk and water in the beginning

    m i l k : water total

    50 L : 0 = 50

    after 5 litres milk taken out and adding water

    Milk : water = 45 L : 5 L = 9:1

    again 5 litres milk taken out and 5 litres water added

    स्रोत : www.quora.com

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    Mohammed 1 month ago
    4

    Guys, does anyone know the answer?

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