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    what is the angle of incidence of a ray if the reflected ray is at an angle of 90 to incident ray

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    Q.13 What Is The Angle Of Incidence Of A Ray

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    Q.13 What is the angle of incidence of a ray if the reflected ray is at an angle of 90° to the incident ray?

    Answer :

    If the reflected ray is at the angle of 90 degrees to the incident ray, then the angle of incidence is 45 degrees.

    According to the law of reflection, the angle of incidence is equal to the angle of reflection.

    Therefore, the angle of incidence and the angle of reflection both are equal to

    90/2 = 45 degrees.

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    स्रोत : www.trustudies.com

    What is the angle of incidence of a ray if the reflected ray if the reflected ray is at an angle of 90 degree to the incident ray? Answer is 45 degree. But my physics teacher tells that answer in 90 degree . Please explain.

    What is the angle of incidence of a ray if the reflected ray if the reflected ray is at an angle of 90 degree to the incident ray? Answer is 45 degree. But my physics teacher tells that answer in 90 degree . Please explain.

    Byju's Answer Standard VIII Physics Laws of Reflection What is the a... Question

    What is the angle of incidence of a ray if the reflected ray is at an angle of 90 degree to the incident ray?

    Open in App Solution

    We know that the angle of incidence is equal to the angle of reflection.

    ∠i = angle of incident.

    ∠r = angle of reflection.

    Given: ∠i + ∠r = 90°

    Since ∠i = ∠r hence;

    ∠i + ∠i = 90° Or, 2∠i = 90° Or, ∠ i= 45°.

    Thus, the angle of incidence is 45°.

    Suggest Corrections 56 SIMILAR QUESTIONS

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    What is the angle of incidence of a ray if the reflected ray is at an angle of 90 degree to the incident ray?

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    Q. A ray of light from a denser medium strikes a rare medium at angle of incidence i as shown in the figure. The reflected and refracted rays make an angle of 90°with each other. The angles of reflection and refraction are r and r'. The critical angle between them is

    (a) sin^-1(tanr) (b) sin^-1(tani) (c) sin^-1(tanr') (d) tan^-1(tani)

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    स्रोत : byjus.com

    What is the angle of incidence of a ray if the reflected ray is at an angle of 90° to the incident ray?

    Answer (1 of 3): By the Laws of Reflection, angle of incidence i = angle of reflection r. Since the reflected ray(angle of reflection r) and the the incident ray(angle of incidence i) are at 90 degrees to each other, angle of reflection r = angle of incidence i = (90/2) = 45 degrees.

    What is the angle of incidence of a ray if the reflected ray is at an angle of 90° to the incident ray?

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    Sort Nand Kishor Mandal

    A Government Teacher, Now. (1998–present)Author has 206 answers and 140.2K answer views2y

    Here,the angle formed by reflected ray with the incidence ray =90°

    So,the angle of incidence(i)=?

    A/q

    I+r=90°. [According to the laws of the reflection of light i=r]

    =>i +I = 90° =>2i =90° =>i =90°/2 =>I =45°

    Hence,the angle of incidence=45° ,And.

    Note-If it is helpful for you upvote and follow me for more answers.

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    What is the angle of incidence of a ray if the reflected ray is at an angle of 90 degree to the incident ray?

    By the Laws of Reflection, angle of incidence i = angle of reflection r. Since the reflected ray(angle of reflection r) and the the incident ray(angle of incidence i) are at 90 degrees to each other, angle of reflection r = angle of incidence i = (90/2) = 45 degrees.

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    If the incident ray and reflected ray have equal angles, what will be the value for the angle of incidence and reflection?

    Angles of incidence and reflection are measured relative to a normal to the reflection surface, i.e., relative to a line perpendicular to the reflection surface. This means that the incident and reflected angles share the normal. The angle of reflection is always equal to the angle of incidence. If the angle of incidence is

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    What is the angle of incidence of a ray if the reflected ray is at an angle of 90 degree to the incident ray?

    Normally, if the incidence angle is 45 theen the reflection angle is bound to be 45, both angles measured from the mirror surface. Now the angle between insident and reflected ray will be 45+45=90.

    I hope it helps, yet I suggest the use of a plot for clarification.

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    What is the angle of an incident ray if the reflected ray and the refracted ray form a 90 degree angle?

    For refraction, Snell’s law stated that

    n sin(theta) = n’ sin(theta’).

    For reflection, we know the angle of incidence (theta) is equal to the angle of reflection.

    So if the refracted and reflected rays form a 90 degree angle, then we know that

    theta + theta’ = 90 deg.

    So you have two equations.

    theta’ = 90 - theta

    sin(theta) = n sin(90 - theta). Assuming the first medium is air.

    We know that sin(a-b) = sin(a) cos(b) - cos(a) sin(b).

    sin(90) = 1 and cos(90) = 0, so

    sin(90 - theta) = sin(90) cos(theta) - cos(90) sin(theta). This means that sin(90-theta) = cos(theta).

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    The angle between the incident ray and reflected ray in 110 so what will be the angle of reflection?

    Assuming the ray hits an ideal surface, the angle of incidence will be equal to the angle of reflection, as they are both adjacent to a line perpendicular to the surface (normal line), or otherwise:

    θ incidence = θ reflection

    θincidence=θreflection

    स्रोत : www.quora.com

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