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    while measuring acceleration due to gravity with simple pendulum if percentage errors in the measurement of length and time period are 2% and 1% respectively, then maximum percentage error in the measurement of acceleration due to gravity is

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    get while measuring acceleration due to gravity with simple pendulum if percentage errors in the measurement of length and time period are 2% and 1% respectively, then maximum percentage error in the measurement of acceleration due to gravity is from screen.

    The percentage errors in the measurement of length and time period of a simple pendulum are 1% and 2% respectively. Then, the maximum error in the measurement of the acceleration due to gravity is

    The percentage errors in the measurement of length and time period of a simple pendulum are 1% and 2% respectively. Then, the maximum error in the measurement of the acceleration due to gravity is

    Byju's Answer Standard XII Physics

    Finding Significant Figures

    The percentag... Question

    The percentage errors in the measurement of length and time period of a simple pendulum are 1%and2% respectively. Then, the maximum error in the measurement of the acceleration due to gravity is

    A 8% B 3% C 4% D 6% E 5% Open in App Solution

    The correct option is E

    5%

    Step 1: Given Data:

    The percentage errors in the measurement of length=1%

    The percentage errors in the measurement of the time period=2%

    Step 2: Formula Used:

    Timeperiod(T)=2πlg, where g is the acceleration due to gravity

    Step 3: Calculating the maximum error in the measurement of the acceleration due to gravity:

    The time period of a simple pendulum is given by-

    Timeperiod(T)=2πlg ΔTT=12(Δll−Δgg) Δgg=Δll−2ΔTT

    Maximum percentage error in the measurement of the acceleration due to gravity is-

    Δgg×100=Δll×100+2ΔTT×100

    =1×100+2×2×100 =5×100=5%

    Hence option E is the correct answer.

    Suggest Corrections 3 SIMILAR QUESTIONS

    Q.

    The percentage errors in the measurements of the length of a simple pendulum and its time period are 3% and 5% respectively. The maximum error in the value of the acceleration due to gravity obtained from these measurements is

    Q. Length

    l

    and Acceleration due to gravity

    g are measured with ± 6 % and ± 4 %

    errors respectively. The percentage error in determination of the Time period of a simple pendulum will be,

    Q. The acceleration due to gravity is measured by using simple pendulum . If 'a ' and 'b' are relative errors in me?surement of length and time period respectively then percentage error in the measurement of acceleration due to gravity will be??Q. The acceleration due to gravity is measured on the surface of earth by using a simple pendulum. If Alfa and beta are relative errors in the measurement of length and time period respectively, then percentage error in the measurement of acceleration due to gravity is?Q. In an experiment to determine acceleration due to gravity by simple pendulum, a student commits 1 % positive error in the measurement of length and 3% negative error in the measurement of time period. The percentage error in the value of will be :

    View More

    स्रोत : byjus.com

    The percentage errors in the measurement of length and time period of a simple pendulum are 1

    Click here👆to get an answer to your question ✍️ The percentage errors in the measurement of length and time period of a simple pendulum are 1

    Question

    The percentage errors in the measurement of length and time period of a simple pendulum are 1% and 2% respectively. Then, the maximum error in the measurement of acceleration due to gravity is:

    A

    3%

    B

    4%

    C

    6%

    D

    5%

    Medium Open in App Solution Verified by Toppr

    Correct option is D)

    Was this answer helpful?

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    स्रोत : www.toppr.com

    The percentage errors in the measurement of length and time period of a simple pendulum are 1% and 2% respectively. Then, the maximum error in the measurement of acceleration due to gravity is

    Time period of simple pendulum is T=2pisqrt((l)/(g)) or (DeltaT)/(T)==(1)/(2)((Deltal)/(l)-(Deltag)/(g)) implies(Deltag)/(g)=(Deltal)/(l)-(2DeltaT)/(l) therefore Maximum percentage error in g, (Deltag)/(g)xx100=(Deltal)/(l)xx100+(2DeltaT)/(T)xx100 =1xx100+2xx2xx100=5xx100=5%

    Home > English > Class 12 > Physics > Chapter > Practice Set 10 >

    The percentage errors in the m...

    The percentage errors in the measurement of length and time period of a simple pendulum are 1% and 2% respectively. Then, the maximum error in the measurement of acceleration due to gravity is

    Updated On: 27-06-2022

    ( 00 : 22 ) ADVERTISEMENT Text Solution Open Answer in App A 0.08 B 0.03 C 0.04 D 0.05 Answer

    The correct Answer is D

    Solution

    Time period of simple pendulum is

    `T=2pisqrt((l)/(g))` or `(DeltaT)/(T)==(1)/(2)((Deltal)/(l)-(Deltag)/(g))`

    `implies(Deltag)/(g)=(Deltal)/(l)-(2DeltaT)/(l)`

    `therefore` Maximum percentage error in g,

    `(Deltag)/(g)xx100=(Deltal)/(l)xx100+(2DeltaT)/(T)xx100`

    `=1xx100+2xx2xx100=5xx100=5%`

    Answer

    Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

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